Given that at 10 degrees Celcius, 8.9 x10^-5 g of AgCl(s) will dissolve in 100 mL of water
2006-12-29 06:38:21 · 3 answers · asked by trakstar16 1 in Science & Mathematics ➔ Chemistry
solubility is measured in moles/liter so:
change grams to moles: divide grams of AgCl by the formula mass of AgCl
change mL to liters: divide 100 mL by 1000
use: Molarity = moles/liters to calculate Molarity
2006-12-30 07:55:22 · answer #1 · answered by The Old Professor 5 · 2⤊ 0⤋
First ascertain what number energy are required to enhance the temp, then convert energy to Joules. 5 energy are required with the aid of fact the definition of calorie is the quantity of warmth had to enhance a million g of water a million degree celsius. a million Joule = .239 calorie So divide 5 by .239 your answer is 20.ninety two Joules
2016-12-18 21:16:01 · answer #2 · answered by ouelette 4 · 0⤊ 0⤋
at temp=10 c
8.9*10^-5g dissolve in water
107 gm of agcl=1mol of agcl
8.9*10^-5 gm=(1/107)*8.9*10^-5 mol of Agcl
therefore
its solubility will be (in mol/lit)
number of moles of solute(ie Agcl) divided by volume of water(in lit)
{(1/107)*8.9*10^-5 mol }/(100/1000 lit)
or
(1/107)*8.9*10^-4 mol / lit
8.3177*10^-6 mol/lit (ans)
2006-12-29 07:05:44 · answer #3 · answered by miinii 3 · 1⤊ 0⤋