Do you mean neutron degenerate matter like the core of a Neutron star or the fictional material neutronium from Star Trek, etc?
The problem with real neutronium (or neutron degenerate matter as found in neutron stars) is that as the pressure needed to sustain it causes electrons to bond with protons to form neutrons, creating a substance composed almost entirely of neutrons.
The tighter the compression, the higher the density. Therefore the mass of neutronium is indeterminate and can increase up until it reaches an as yet unknown limit. Science suggests that at some limit, such a substance can collapse into a black hole.
The skin of an average adult human weighs about 8-10 lbs and covers an area of about 22 square feet. If you could assign a definite mass to neutronium (which you can't), then you could possibly calculate your new weight with Neutronium skin.
2006-12-29 04:09:44
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answer #1
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answered by Mr 51 4
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Try this on for size:
First, calculate your mass density (slugs per ft^3) rho(m) = m/V =(w/g)/V; where m = your mass in slugs, w = 185 lb., g = 32.2 ft/sec^2, and V = your body volume in ft^3.
Second, assume a rho(N) = (W/g)/V = M/V; where W = the weight of the neutronium now shaped into your volume (V) and M = the mass of your neutronium skin (we can discount the mass of your innards because that will be waaay smaller than the neutronium).
So then we take the ratio W/w = rho(N)/rho(m); so that we have W = w [rho(N)/rho(m)] As the average neutron star density is about 1 X 10^14 times the density of water [See source.] and as the human body is mostly water, we can guesstimate your new weight will be about W = w [rho(N)/rho(m)] = 185 (1 X 10^14) = 185 X 10^14 pounds. You must go on a diet.
PS: If you choose to figure the volume and density of just the skin, you will still get the same answer. Why? Because W/w = M/V//m/V and both M and m would be multiplied by the same percentage (e.g., kM and km, where k is that percentage of mass belonging to the skin) and your skin's volume is the same regardless what it is made of. In other words, the ratio W/w = rho(N)/rho(m) is unchanged if you take the whole body mass or the skin mass.
2006-12-29 12:40:22
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answer #2
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answered by oldprof 7
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Assuming for a minute that it is just your skin, which turns into solid neutronium, and assuming that this freak occurence obeys the law of conservation of matter, you would weight about 185 pounds, and your skin would be approximately one neutron's width in thicnkess.
Oh, also if your skin had not been ripped apart in the process, you would likely be crushed down to the size of a grain of sand or smaller, and much of your body would also be converted to solid neutronium by the pressure.
I suggest you avoid any freak occurences like this that might be happening in your neighborhood, it's bound to be ugly.
2006-12-29 12:16:57
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answer #3
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answered by ye_river_xiv 6
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Since neutronium weight is 0, Now you to find the weight of your skin. That you do by finding the volume of your body, which you do by immersing yourself completely in tub and look at the displacement. or u can approximate the weight form this web site
http://www.infoplease.com/askeds/weight-human-skin.html
so your total weight is between 173 to 175 pounds
2006-12-29 12:26:23
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answer #4
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answered by Suhas 2
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WOW that is hard I am good I mean great at the subjects but I have no idea. Heavy very heavy in the 300s or 400s. first estimate the teacher should have taught you how to do this. Hope this helps
2006-12-29 12:12:04
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answer #5
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answered by Maccabee 3
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If you can tell us the mas of neutronium that would help. You are reading too much science fiction dude.
2006-12-29 12:11:39
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answer #6
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answered by Sergio__ 7
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You would be so heavy that your body would be crushed under the weight of your own skin. Getting you on a pair of scales wouldn't be too hard, but you wouldn't be alive to know the answer, so who cares?
2006-12-29 12:10:46
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answer #7
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answered by dalman99uk 2
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are you talking to your computer because it doesnt know how to answer that question and it doesnt even know what those words really mean
the same as your replacement on a neutronium scale
2006-12-29 12:30:43
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answer #8
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answered by Anonymous
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I'm good in math and biology but I guess not that good. My guess is very heavy.
2006-12-29 12:09:48
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answer #9
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answered by unicornfarie1 6
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Ur weight might gets reduced tremendously
2006-12-29 13:31:51
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answer #10
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answered by venkat 1
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