(y5)3(y3)2/(y4)4
2006-12-29 00:59:54 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
answer is y^5
numerator
(y^5)^3 = y^15
(y^3)^2 = y^6
y^15 x y^6 = y^21
denominator
(y^4)^4 = y^16
then
y^21/y^16 = y^5
2006-12-29 01:04:32 · answer #1 · answered by bsah 3 · 0⤊ 0⤋
(y5)3(y3)2 over (y4)4
operanting exponents:
15 + 6 - 16 = 5
So, the answer is y^5
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2006-12-29 09:44:04 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
Some basics:
When you say "little numbers", you mean exponents. The "proper" way to write them when you don't have the little numbers is y^5 instead of y5.
(y^a)b = y^(ab)
(y^a)(y^b) = y^(a+b)
(y^a)/(y^b)=y^(a-b)
Given those, let's work with the initial equation.
(y^5)³ (y³)² / (y^4)^4
= y^(3x5) y^(3 x 2) / y^ (4x4)
= y^15 y^6 / y^16
= y (15 + 6) / y^16
= y^21 / y^16
= y^(21-16)
= y^5 --> The answer is y^5, or y with the little 5 above it.
2006-12-29 11:12:57 · answer #3 · answered by Wendy C 2 · 0⤊ 0⤋
(y5)3 * (y3)2 /(y4)4 = (y15)(y6)/y16 = y5
2006-12-29 09:36:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
i forgot the solution..im sorry!
2006-12-29 09:04:27 · answer #5 · answered by Angelika 1 · 0⤊ 1⤋