what are the isomers for C5H10?

Answer 1

C5H10 is the formula of an alkene since it follows the formula of CxH2x, where x is any integer. CxH2x+2 is an alkane.
This means you have one double bond, or a ring structure.

I get 5 non-ring isomers:
1-pentene
2-methyl-1-butene
3-methyl-1-butene
2-pentene
2-methyl-2-butene

4 Ring structures:
Unlikely structures are:
1-methylcyclobutane. Due to its configuration, its structure is under heavy strain and is unlikely to hold its ring formation. Also 1,1-dimethlypropane, 1,2-dimethlypropane, and ethlycyclopropane, a triangle, are also strained structures. And don't forget cyclopentane.

Answerer #1 has nice structures drawn out, but has them incorrectly named as alkanes. If there is a double bond, it is an alkENE.

Check the link for more info on IUPAC nomenclature.

Answer 2

Yes , the third isomer you drew is different from the second. There are some more you havent found yet try taking what you have and moving the double bond around a bit more :p i can see two more.

Answer 3

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RE:
what are the isomers for C5H10?

Answer 4

OK...the isomers are as follows:

CH3CH2CH2CH=CH2 pent-1-ene

CH3CH2CH=CHCH3 pent-2-ene, of which there are 2 geometric isomers: trans-pent-2-ene and cis-pent-2-ene

CH3CH2C(CH3)=CH2 2-methylbut-1-ene

(CH3)2CHCH=CH2 3-methylbut-1-ene

(CH3)2C=CHCH3 2-methylbut-2-ene

Another isomer, difficult to draw, is cyclopentane.

Also, methylcyclobutane, which will be strained and therefore unstable.

Also, theoretically, 1,1-dimethylcyclopropane and 1,2-dimethylcyclopropane, again both strained and unstable.

Answer 5

C5H10 means pentane.It has 3 isomers as n-pentane,iso-pentane & neo-pentane.

Answer 6

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They want you to give the total number of olefin and ring compounds. CH2=CHCH2CH2CH3, CH3CH=CHCH2CH3, CH2=C(CH3)CH2CH3, (CH3)2C=CHCH3, (CH3)2CHCH=CH2, cyclopentane, methylcyclobutane, 1,1-dimethylcyclopropane, 1,2-dimethylcyclopropane, ethylcyclopropane I get 10

Answer 7

I add one more cyclic structure to the Claudeaf answer:

ethyl-cyclopropane

Answer 8

is there 3-methylbut-2-ene??

Answer 9

H2C=CH-CH2-CH2-CH3 (1-pentene)

H3C-CH=CH-CH2-CH3 (2-pentene)

H2C=C-CH2-CH3 (2-methyl-1-butene)
...........|
...........CH3

H2C=CH-CH-CH3 (3-methyl-1-butene)
..................|
..................CH3

H3C-C=CH-CH3 (2-methyl-2-butene)
..........|
.........CH3



.........CH3
..........|
CH2-CH2 -CH3 (1,1-dimethyl-cyclopropane)
..\...../
....CH2

CH2-CH2-CH2 -CH3 (1,2-dimethyl-cyclopropane)
............\...../
..............CH2

CH2-CH2 -CH2-CH3 (1-ethyl-cyclopropane)
..\...../
....CH2



CH2-CH2-CH3 (1-methyl- cyclobutane)
|.........|
CH2-CH2

CH2-CH2-CH2 (cyclopentane )
|..................|
CH2---------CH2
(sry it looks this bad, it should have tha shape of a penthagon, but i'd rather kill myself than try to draw it here)


sorry about all those dots i put there, but i couldn't find any other way to make the carbons stay where they should

later edit: thank's, answerer nr2. my english kind of sucks since i'm not a native.. i got carried away by the spelling and i forgot the essential..