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2. x^2 + 6x -5 = 0

4. 4x^2 + 20x = 0

6. 3x^2+ 10x + 8 = -17x -2

2006-12-28 14:46:41 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

2 is already in standard form. a = 1, b = 6, c = -5.

4 is already in standard form. a = 4, b = 20, c = 0.

6:

3x² + 10x + 17x + 8 + 2 = 3x² + 27x + 10

a = 3, b = 27, c = 10.

2006-12-28 14:49:39 · answer #1 · answered by Jim Burnell 6 · 0 0

The standard form of a quadratic equation is
ax^2 + bx + c

the first two are in standard form already -- you should be able to figure out what a, b, and c are

for #6, add 17x+2 to both left hand side and right hand side so that you have "0" on the right and the left hand side takes the standard form.

2006-12-28 14:53:41 · answer #2 · answered by newlex 2 · 0 0

2. Fernan is right, that's stated as the conventional Theorem of Algebra: the variety of recommendations to any polynomial equation is comparable to the degree of the polynomial. So, a 4th degree polynomial equation has precisely 4 recommendations. The degree of a quadratic equation is two, so each has precisely 2 recommendations. be careful, some quadratic equation use the comparable variety as the two recommendations. that's stated as the multiplicity of recommendations. ProfRay

2016-10-28 14:41:35 · answer #3 · answered by uday 4 · 0 0

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