(3x-cubed - 2x-to the first power + 7y-to the first power)
I came up with -124 but the answer is apparently undefined? How so?
2006-12-28 14:36:44 · 8 answers · asked by feedazombie 1 in Science & Mathematics ➔ Mathematics
Almost forgot. x= -3, y= -7
2006-12-28 14:37:17 · update #1
3x^3-2x+7y
=3(-3)^3-2(-3)+7(-7)
=3(-27)+6-49
=-81+6-49
= -130+6
=-124
So your answer is perfectly correct.
2006-12-28 15:35:57 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
3x^3-2x+7y x= -3, y= -7
3(-3)^3-2(-3)+7(-7)
-81+6-49=-124
I agree with you . The book must be wrong. :)
seriously, as stated, the answer is -124.
2006-12-28 22:42:00 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
this is not correct. You forgot to rise x in third power
(3x)^3-2x+7y=
27x^3 - 2x+7y
Now, we know that x=-3 and y=-7, we obtain
27*(-3)^3-2*(-3)+7*(-7)=
27*(-27)+6-49=729-43=686
2006-12-28 22:47:57 · answer #3 · answered by tanie 1 · 0⤊ 0⤋
3x³ - 2x + 7y
x = -3
y = -7
3*-27 - 2*-3 + 7*-7 =
-81 + 6 - 49
= -124
2006-12-28 23:28:34 · answer #4 · answered by M. Abuhelwa 5 · 0⤊ 0⤋
(3x^3)-(2x^1)+(7y^1)=?
x= -3, y= -7
(3*-3^3)-(2*-3)+(7*-7)=
-81+6-49= -124
i got the same thing as you....
2006-12-29 00:03:01 · answer #5 · answered by tedovas 1 · 0⤊ 0⤋
(3x^3 -2x + 7y)
(3(-3)^3) (-9^3) result: (-729)
-2(-3) result: (6)
7(-7) result: -49
-729 +6 -49 = -772
-772 Final Answer
2006-12-28 22:56:12 · answer #6 · answered by jm 3 · 0⤊ 1⤋
Where's the equation here? I see no equation
or problem in your question.
2006-12-28 22:40:20 · answer #7 · answered by steiner1745 7 · 0⤊ 0⤋
you must use praneses for your equation if you currect it you can find your answers above
2006-12-28 23:27:16 · answer #8 · answered by muhammad 1 · 0⤊ 0⤋