Multiply the second equation by -3:
5x - 3y = 14
-6x + 3y = -18
----------------
-x = -4
x = 4
Plug that in the second equation:
2(4) - y = 6
8 - y = 6
-y = -2
y = 2
Check:
5(4) - 3(2) = 20 - 6 = 14
2(4) - 2 = 8 - 2 = 6
2006-12-28 13:32:06
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answer #1
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answered by Jim Burnell 6
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5x - 3y = 14
2x - y = 6
multiply the 2nd equation by negative 3.
5x - 3y = 14
-6x + 3y = -18
add the two equtions.
-x = -4
divide by negative 1.
x = 4
plug it in to find y.
2(4) - y = 6
8 - y = 6
-y = -2
y = 2
Check.
5(4) - 3(2) = 14
20- 6 = 14
that works.
2(4) - 2 = 6
8 - 2 = 6
that works.
solution (4,2)
hope I helped!
2006-12-28 21:34:51
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answer #2
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answered by Lisaya 1
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A solution using ONLY the addition method:
Multiply 2x -y = 6 equation by -3
You get -3(2x-y=6) => -6x + 3y = -18
ADD 5x - 3y = 14 equation to above
-6x + 3y = -18
5x - 3y = 14
------------------
-1x + 0 = -4 >>> x = 4
NOW
Multiply 5x-3y=14 equation by +2
2(5x-3y=14) => 10x -6x=28
Multiply 2x-y=6 equation by -5
-5(2x-y=6) => -10x + 5y=-30
ADD
10x - 6x = 28
-10x + 5y = -30
--------------------
0 - 1y = -2 >>> y = 2
Soooo... you get x=4 and y=2
All by just using addition method!
2006-12-28 21:56:38
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answer #3
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answered by lostlatinlover 3
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5x – 3y = 14......(1)
2x – y = 6......(2)
3x(2) - 1: x = 4
Substitute x = 4 into (2),
y = 2
Check:
5(4) - 3(2) = 4
2(4) - 2 = 6
2006-12-28 21:24:31
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answer #4
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answered by sahsjing 7
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5x – 3y = 14.....Eq 1
2x – y = 6.....Eq 2
Consider Eq 2
2x - y = 6
2x = 6 + y
x = (6 + y)/2
Substitute in Eq 1
5x – 3y = 14
5(6 + y)/2 - 3y = 14
(30 + 5y)/2 - 3y = 14
(30 + 5y - 6y)/2 = 14
(30 - y)/2 = 14
30 - y = 28
-y = 28 - 30
-y = -2
y = 2
Now substitute the value of y in Eq 2
2x - y = 6
2x - 2 = 6
2x = 8
x = 4
x = 4, y = 2 is the solution
2006-12-28 21:57:01
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answer #5
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answered by Akilesh - Internet Undertaker 7
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5x - 3y = 14 (i)
2x - y = 6 (ii)
Multiply (ii) by -3:
5x - 3y = 14 (i)
-6x + 3y = -18 (iii)
Add (i) & (iii):
-x = -4
x = 4.
Solve (ii) for y:
2(4) - y = 6
8 - y = 6
-y = -2
y = 2.
2006-12-28 21:32:36
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answer #6
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answered by S. B. 6
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