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three people went to buy a tv at a shop they baught it for 30$
and after buying it the shop manager made them a discount 5$
so he went to them at their house personally and he insisted to give them the 5$ discount its their right
but he was a lil greedy so he gave everyone of them 1 $ and he put 2$ into his pocket
so the total sum of the money the 3 people paid is 27$ + the 2$ the man put in his pocket the sum is 29$ where the hell did the last dollar go????????????????????????????...

2006-12-28 12:31:56 · 11 answers · asked by Mostafa Hammouda 1 in Science & Mathematics Mathematics

11 answers

If you read your question to yourself really slowly, you might realize it MAKES NO SENSE...you are comparing apples with oranges...

2006-12-28 12:46:45 · answer #1 · answered by Anonymous · 0 0

The problem is your last sentence: "so the total sum of the money the 3 people paid is 27$ + the 2$ the man put in his pocket the sum is 29$"

That's not right!

The total sum of the money the three people paid is indeed 27$. However the TV cost 25$ (taking the discount into account). And so the extra $2 that they paid is exactly the extra $2 that the shop manager has in his pocket.

2006-12-28 12:39:47 · answer #2 · answered by Christine F 2 · 0 0

2 ways to look at it. 1st, where is the money.

3 people / manager / total
30 / 0 / 30
0 / 30 / 30
3 / 27 / 30

2nd way, gains and losses
3 people / manager / total
0 / 0 / 0
-30 / 30 / 0
-27 / 27 / 0

This problem usually has a bellboy who acts as middleman between the manager (of the hotel) and the guests. That helps confuse the issue, but also makes clearer what the error is.

When the manager gives back $3 of the $30 he had, he has $27 left. The $2 he put in his pocket was part of the $27 he already had and certainly should not be added (again) to the $27 the people paid. That would be counting it twice.

2006-12-28 14:00:02 · answer #3 · answered by Philo 7 · 0 0

Actually the explanation is wrong it correct that they paid 27 but because of $25 and 2 dollars that the store manager kept... but the number that should be added to $27 is $3 for the money return to them. its a simple accounting problem...
Debit = credit
$27 cost +$3 returned = $25 total paid + $5 discount

2006-12-28 20:58:06 · answer #4 · answered by Anonymous · 0 0

1. Tv was bought for $30
2. Shop guy leaves with $5, leaving $25 at the shop.
3. Shop guy gives to the gents $3, making the cost $27
4. Shop guy returns with $2 to the shop where the other $25 is, making a total of $27, matching the amount paid by the 3 gents.

You don't add assets and liabilities together, which caused the confusion.

2006-12-28 12:42:01 · answer #5 · answered by Scythian1950 7 · 0 0

You're looking at it wrong.
They paid $30, and got back $1 each, so they paid $27. The shop owner got $25 (the discounted price) plus the 2 dollars he pocketed. That's the full $27 accounted for.

2006-12-28 12:43:10 · answer #6 · answered by so far north 3 · 0 0

I saw one similar the other day.

The 3 people paid $30. With the discount, they only paid $25. The manager kept $2, and gave them $3. 25 + 3 + 2 = $30.

2006-12-28 12:40:56 · answer #7 · answered by Anonymous :) 5 · 0 0

You did it wrong.
$30 - the discount ($5) = $25
$25 + the $3 he gave back= $28
$28 + the $2 he put in his pocket = $30.

2006-12-28 12:37:47 · answer #8 · answered by Ənigma 2 · 0 0

It's one of the oldest "trick" problems in the book. It's usually told as "Three guys go into an motel..." blah blah blah. The trick is that it's $27 MINUS the two that went into the guy's pocket, not PLUS. Draw a little diagram of what's happening on paper and it becomes quite clear.

2006-12-28 12:40:06 · answer #9 · answered by DinahMac 1 · 0 0

They paid 30, got 3 back, he kept 2. That's 30.

2006-12-28 12:36:59 · answer #10 · answered by eri 7 · 0 1

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