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TOTO is a lottery. The total available numbers are from 1 to 45. Only 6 numbers will be drawn. If all the 6 numbers match, you win the first prize! The 6 numbers will not repeated. How to culculate the probability to strike the 1st prize?

2006-12-28 01:33:19 · 6 answers · asked by WilliamC 1 in Science & Mathematics Mathematics

6 answers

the calculations, use the method n C r or n CHOOSE r=
45 Choose 6= 8,145,060

these are factorials that break down to
45*44*43*42*41*40/6*5*4*3*2*1 = 8,145,060

2006-12-28 01:45:09 · answer #1 · answered by James O only logical answer D 4 · 0 0

The total number of 6-combinations from a set of 45 numbers is:

C(45, 6) = 45 x 44 x 43 x 42 x 41 x 40 / (6 x 5 x 4 x 3 x 2 x 1)

or 8145060

So your chances are 1 in 8145060.

2006-12-28 01:37:42 · answer #2 · answered by Jim Burnell 6 · 0 0

Since the order does not matter, this is a combinations problem. There are 6 correct numbers and you need all 6 so the top of the probability fraction is 6C6.

There are 45 total numbers so the bottom is 45C6

2006-12-28 01:37:47 · answer #3 · answered by hayharbr 7 · 0 0

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2016-03-13 22:47:57 · answer #4 · answered by Anonymous · 0 0

There are C(45,6) ways to select 6 numbers, that is 45*44*43*42*41*40/6!.

There is only one good choice(matching all six numbers).

So probability is 1/C(45,6) = 1/8145060.

2006-12-28 01:42:17 · answer #5 · answered by mlpkr 2 · 0 0

To translate all those other correct answer, odds are a little worse than one in eight million.

2006-12-28 02:21:28 · answer #6 · answered by a_math_guy 5 · 0 0

probablility = possible outcome/ all outcome
P(1st prize)=1/(45C6)=1/8145060

2006-12-28 01:57:32 · answer #7 · answered by Math Student 4 · 0 0

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