2006-12-28 00:45:35 · 4 answers · asked by deerdog13 1 in Science & Mathematics ➔ Physics
By Ohm's Law, E = I * R if you make the operation
I = E/R and plug in some test figures as,
I = 100v/100Ω; I = 1 A. Now change the voltage as
I = 200v/100Ω; I = 1/2A.
Just change the basic formula around to get what you need.
E=I*R, I=E/R, R=E/I, plug in the 2 known values and do the arithmetic.
2006-12-28 00:57:06 · answer #1 · answered by credo quia est absurdum 7 · 0⤊ 0⤋
By Ohms Law
So long as the physical state of the conducter is unchanged,the potential difference bears a constant ration with current.
V=I*R
Thus when V increases , with resistance constant
Current increases.
2006-12-28 08:51:26 · answer #2 · answered by Som™ 6 · 2⤊ 0⤋
current is the amount of "electric particles" that "flows" through cable. (well not a very appropriate definition that I would consider as ultimately correct, but you can think it as so for simplification)
When the voltage is increased it means the kinetic energy difference between two points in the cable are increased, that would mean that the flow of the electricity (current) would increase.
2006-12-28 09:03:32 · answer #3 · answered by Lie Ryan 6 · 0⤊ 0⤋
Current will increase according to the equation: V=IR.
2006-12-28 12:56:51 · answer #4 · answered by Math gal 2 · 0⤊ 0⤋