How many products would result from C4H10 + Cl2?

Question

And what's the name for C4H10 in English?
In my native language it's butan.
I've seen only two products in my book ,but I think there are a lot more in practice.

Answer 1

Lancenigo di Villorba (TV), Italy

I know that C4H10 is so-called "formula bruta" of butan compounds, a family of light hydrocarbons who belongs to "Alkanes" (well known as "satured" hydrocarbons CnH2n+2, where for you is n=4). Among them we remark :
i) n-butan (normal-butan, linear carbon-chain);
ii) iso-butan (iso-butan, T-shaped carbon-chain),
the former and latter are related by structural isomery.
Thus, you have two chemical species who can react with chlorine (Cl2), as you indicate.
This reaction is lead in chemical industry for chloro-derivatives synthesis (e.g., solvents in our commodities) : their industrial processes are conducted in gas mixtures, irradiated by U.V. emission (photo-catalysis) and in reactors continuously feeded by pre-hot and anhydrous streams of reactive parts.
Your question belongs in "in serie" reaction, so-called because several step's reaction are known and they result aligned like a cascade : thus, the chemical intermediates of these steps can react even and generate other compound, for you exists hydrocarbon who proceed sobstitution of their hydrogen atoms with chlorine ones. I can define it "chlorination of butan isomer's mixture (e.g., LPG C3-less)". I can also say that one among greatest chemist (J.B. Dumas, XIX century) have formulated the idea of "type-theories" as speculation of his studies about chlorination of candles in His Majesty's ball-room : in that times, F. Gerhardt, Dumas's pupil, thought that hydrocarbons are fundamental principles of every organic matters.
But...what's my answer to your numerical question?
The practical answer to your question is about industrial remarks : distillation towers highlight mixtures of several chloro-derivatives, obviously considerable amounts of mono-chloro compounds, the smaller quantities the greater number of chlorine atoms in the derivatives. For example, on basis of the combination possibilities and IUPAC denomination rules, they follow :
i) 4 mono-chloro compounds (2 by n-C4, 2 by i-C4);
ii) 10 di-chloro compounds (6 by n-C4, 4 by i-C4);
iii) tri- and other following chloro substitued.

I hope this can satisfacted you

Answer 2

n-Butane, like all hydrocarbons, undergoes free radical chlorination providing both 1-chloro- and 2-chlorobutanes, as well as more highly chlorinated derivatives. The relative rates of the chlorination is partially explained by the differing bond dissociation energies, 425 and 411 kJ/mol for the two types of C-H bonds. 2 primary products, but since each of the 10 h atoms can be substituted a total of 1024...

Answer 3

Butane is the English name for C4H10.

It has two isomers, one a straight chain (called normal butane) and the other branched (called isobutane).

If the chlorine is in excess and mixed with n-butane, the mixture of dichlorobutanes will be as follows:
1,1-dichlorobutane = 6.113%
1,2-dichlorobutane = 23.644%
1,3-dichlorobutane = 47.207%
1,4-dichlorobutane = 23.036%

Trichloro and other butanes could also be formed.

The isobutanes would give similar results.