Home work help?For math?

Question

Find thr equation of the line passinh through the given points.


1. (1,5) (2,7)

Answer 1

***Step 1-find the slope (rise over run)
(7-5)/(2-1)--> 2/1-->2

now that you know the slope is two...

***Step 2-plug in what you know into the point slope formula which is...
(y-y1)=m(x-x1)

choose either (1,5) or (2,7) to enter for Y1 and X1
in this case i'll do the (1,5)

y-5=2(x-1)
y-5=2x-2

***step 3-isolate "y"

y-5=2x-2
y=2x-2+5 (add 5 to both sides of the equation)
y=2x+3 (simplify)

and now you have your answer y=2x+3

g'luck

Answer 2

Ok first you need to plot these points. Now you can probably see that it is a linear equation. This means that it follows the rule of:
y = mx + c. In this equation, the gradient equals M and the y-intercept is c (the point which this line would cross the y-axis if you drew the whole thing). Now M is:
(Y2 - Y1)/(X2 - X1). In (1,5) let 1 = X1 and 5 = Y1. In (2,7) let 2 = X2 and 7 = Y2. This means M = (7-5)/(2-1) which equals 2. Now using the gradient say that 2 = (y-5)/(x-1), in which case 2(x-1) = y-5. So 2X - 2 = Y-5 therefore Y = 2X + 3. you can also use 7 and 2 for this part if you want. Oh and to find the gradient you can also say (5-7)/(1-2).

Answer 3

MATH, ACTIVITIES and FUN.

http://www.sosmath.com/wwwsites.html

http://www.webmath.com/index.html

http://mathforum.org/dr.math/

http://www.tc.cornell.edu/Services/Education/Gateways/Math_and_Science/mathematics.htm

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http://www.theproblemsite.com/math_games.asp

http://www.internet4classrooms.com/skills_4th.htm

http://www.apples4theteacher.com/math.html

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http://www.center.k12.mo.us/edtech/edm/4.htm

http://www.learningplanet.com/act/mayhem/index.asp

http://www.mathisfun.com/

http://www.sparknotes.com/math/

http://its.leesummit.k12.mo.us/studentsites.htm

http://springfieldpublicschoolsmo.org/depts/edtech/Resources/Math/index.htm

http://www.math.com/

MATH WEBSITES FOR TEACHERS AND STUDENTS

http://www.cumbavac.org/Math.htm

Good luck.

Kevin, Liverpool, England.

Answer 4

let (x1,y1)=(1,5) and (x2,y2)=(2,7)
equationof line passing through (x1,y1) and (x2,y2) is
y-y1=(y2-y1)/(x2-x1) *(x-x1)
y-5=(7-5)/(2-1) *(x-1)
y-5=2/1 *(x-1)
y-5=2(x-1)
y-5=2x-2
2x-y+3=0

Answer 5

maths is a subject which needs practice ."PRACTICE MAKES A MAN PERFECT".so practice or homework is the same thing

Answer 6

R u sure????