2006-12-27 15:07:26 · 8 answers · asked by styles4u 4 in Science & Mathematics ➔ Mathematics
Well, if you want it by factoring, then:
5x^2-125=0,
that is factoring the 5:
5(x^2-25)=0
x^2-25=0
factoring again:
(x+5)(x-5)=0
and you've got your two solutions: 5 and -5
2006-12-27 15:22:50 · answer #1 · answered by Carlos 1 · 3⤊ 0⤋
Subtract 125 from both sides:
5x^2-125=0
Factor out a 5:
5(x^2-25)=0
(x+5)(x-5)=0
x=±5
2006-12-27 23:29:57 · answer #2 · answered by Anonymous · 2⤊ 1⤋
5x^2 = 125
5x^2 - 125 = 0
5(x^2 - 25) = 0
So, x^2 - 25 = 0
Using algebraic identity a^2 - b^2 = (a + b)(a - b)
x^2 - 25 = (x + 5) (x - 5) = 0
Therefore, x = 5 = 0 ..... x = -5
or x - 5 = 0 .... x = 5
So, x = +5 or -5
2006-12-27 23:30:32 · answer #3 · answered by Srinivas c 2 · 3⤊ 1⤋
5x^2=125
x^2=125/5
x^2=25
x=Sqrt25
=(+/-)5
x=+5,x=-5
2006-12-28 00:42:56 · answer #4 · answered by tarena 2 · 0⤊ 1⤋
5x² = 125
5x²/5 = 125 / 5
x² = 25
x² = â25
x = ± 5
The answer is x = ± 5
Insert the x value into the equation
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Checking for +
5x² = 125
5(5)² = 125
5(25) = 125
125 = 125
- - - - - - - - -
Checking for -
5x² = 125
5(- 5) ² = 125
5(25) = 125
125 = 125
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2006-12-28 07:07:11 · answer #5 · answered by SAMUEL D 7 · 0⤊ 1⤋
To solve this by factoring you first must divide the eqn by 5.
Then subtract the right-hand result.
Now you have the diff of 2 squares you should be able to factor it from there.
2006-12-27 23:21:49 · answer #6 · answered by AibohphobiA 4 · 3⤊ 1⤋
5x^2=25
x^2=125/5
x^2=25
x=sqrt(25)
x=(+/-)5
so x=5 and x=-5
2006-12-27 23:09:18 · answer #7 · answered by angel 2 · 4⤊ 1⤋
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2006-12-27 23:15:23 · answer #8 · answered by ? 3 · 1⤊ 4⤋