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To balance simple equations look at each atom, one by one, to see if you have the same number on both sides of the equation. If you don't, put a coefficient (a number in front of the compound) in front of the compound where you have to increase the number of atoms. Keep going back and forth until all atoms are balanced.

1. Look at carbon: there is 1 atom of carbon on both sides of the equation so you don't have to do anything.

2. Look at sulfur: there are 2 atoms of sufur on both sides of the equation so you don't have to do anything (on the product side there is 1 sulfur in the NH4SCN PLUS 1 sulfur in the H2S for a total of 2)

3. Look at N: there is 1 atom of N on the reactant side and 2 atoms of N on the product side. This means you have to put a "2" in front of the NH3 in order to balance the nitrogen.

4. Now you have 6 atoms of hydrogen (2 x NH3) on the reactant side so you need to have 6 on the product side. In the NH4SCN there are 4 hydrogen atoms PLUS in the H2S there are 2 more hydrogen atoms making for a total of 6.

The equation is now balanced.

CS2 + 2NH3 = NH4SCN + H2S

2006-12-28 00:15:39 · answer #1 · answered by The Old Professor 5 · 0 0

start counting the no. of atoms when unbalanced:
Reactant: Product:
C=1 C=1
S=2 S=1,1
N=1 N=1,1
H=3 H=4,2

so lets try to balance:

CS2+(2)NH3=NH4SCN+H2S

Reactant: Product:
C=1 C=1
S=2 S=1,1
N=1(2) N=1,1
H=3 (2) H=4,2

so all in all if: CS2+2NH3=NH4SCN+H2S

Reactant: Product:
C=1 C=1
S=2 S=2
N=2 N=2
H=6 H=6

you now have a balance formula...

CS2+2NH3=NH4SCN+H2S is the ans.

2006-12-28 00:16:20 · answer #2 · answered by maila_venus9193 2 · 0 0

CS2 +2 NH3 = NH4SCN + H2S

2006-12-27 15:00:13 · answer #3 · answered by Anonymous · 0 0

as an occasion: stability this chemical equation. ok + H2O = KOH + H2 it could quite help in case you could first count extensive form the value of their ions first. contained in the 1st chemical equation wherein ok + H2O ok and O in basic terms have a million ion with the aid of fact there are no longer any numbers contained in the wonderful area which understood to be a million even as H has 2 ions with the aid of fact of that 2 beside it. So ok = a million O = a million H = 2 contained in the 2nd chemical equation that's KOH + H2 ok = a million O = a million H = 3 H has 3 ions for the reason that there are 2 Hydrogen in this equation the different hydrogen has a million ion and the different has 2, so a million + 2 = 3 notice: There are no longer any minus in a chemical equation in basic terms plus. Now which you recognize the ions. it quite is time to stability them. ok + H2O = KOH + H2 you're able to do this by trial and mistake, it could take it sluggish yet once you will in basic terms attempt and attempt you will get it. attempt to observe the two equation. contained in the equation on the left ok = a million. contained in the wonderful ok = a million so this element is already stability. The O contained in the left has a million ion and contained in the wonderful it additionally has a million ion so that is stability additionally. enable's see H contained in the left equation H = 2 even as contained in the wonderful H = 3 it is not stability in an attempt to stability it you will desire to positioned some numbers in beggining of a chemical form to make it stability. in this equation to make it stability the equation would desire to be like this. 2 ok + 2 H20 = 2 KOH + H2 for the reason that H isn't stability we positioned a 2 in KOH so as that the H in there'll develop into 2. 2(a million)=2 a million=ion of H so as which will make H develop into 2 ions ands so with the aid of fact the different aspects ok and O. I positioned yet another 2 in H2O so as that the O will develop into 2 additionally. And yet another 2 in okay to make it 2 aswell. in 2 ok +2 H2O ok = 2 H = 4 with the aid of fact 2 accelerated by the ion that's 2 is 4. O = 2 in 2 KOH + H2 ok = 2 H = 4 with the aid of fact 2(a million) + 2 = 4 O = 2 So now they're balanced.

2016-12-18 20:18:31 · answer #4 · answered by Anonymous · 0 0

Starting with 2 sulfur on reactant side, you see that you have 2 on product side. Balanced.

1 N on reactant, 2 on product side. Put coefficient of 2 in front of ammonia (NH3)

1 C on reactant and 1 on product side. Balanced.

Hydrogens are alanced.

2006-12-27 15:17:11 · answer #5 · answered by teachbio 5 · 0 0

It should be A1+VD2+JF3=FK5

2006-12-27 15:03:02 · answer #6 · answered by Sean 2 · 0 3

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