I = I(cm) + Md(d to square). It is right in the case that a body does not turn about its own center-of-mass axis, but about the other axis. If while a body turns about the other axis, it turns about its own center-of-mass axis. Then, I = ( I(cm) + Md (d to square) ) + I(cm). Is it correct?
2006-12-27 12:38:38 · 3 answers · asked by chuong l 1 in Science & Mathematics ➔ Physics
It is not correct.
To find the I(cm), use the same formula.
I = I(cm) + Md(d to square.
In this case, d = 0.
Therefore, I = I(cm) + M x 0 = I(cm)
2006-12-27 13:11:02 · answer #1 · answered by Pearlsawme 7 · 0⤊ 0⤋
You have 1 extra I(cm) that should not be there. While turning about an axis off the CM by a distance d, the inertia about that axis is given by
Ia = I(cm) + md²
That's all
2006-12-27 21:33:24 · answer #2 · answered by Steve 7 · 0⤊ 0⤋
no because this this is unreal situation.
as the body can not rotate at the same time about to Parrnell axis
2006-12-27 20:48:14 · answer #3 · answered by Mohamed K 2 · 0⤊ 0⤋