If 0.77 mol Calcium nitrate dissolved in water makes 660 g of aqueous solution, what is the percent calcium nitrate in the solution ?
2006-12-27 10:41:53 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
how did u get that answer?
i did it out and got 19.13%?
2006-12-27 10:46:00 · update #1
the grams of Ca(NO3)2 0.77 * 164 = 126.28g
the percent of Ca(NO3)2 126.28 / 660 * 100 = 19.13%
2006-12-27 10:50:28 · answer #1 · answered by James Chan 4 · 1⤊ 0⤋
Eee, I didn't get either of those, but here's what I did, if it helps in any way...
Molecular Weight of CaNO3
.77 mol * (164 g Ca(NO3)2/ mol Ca(NO3)2) = 126.28 g CaNO3
That would mean 126.28g CaNO3 of the solution is CaNO3, at this point I found the percentage of CaNO3 by finding the fraction of the mass of CaNO3 in the total mass of solution
126.28 g CaNO3
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660 g solution * 100% = 19.1% CaNO3
since you aren't worried about anything else in the solution and you only know the final mass of the solution with added calcium nitrate, to me it was only a matter of thinking "What's the fraction of A out of B?" Hope this helps :)
2006-12-27 19:08:24 · answer #2 · answered by That Guy! 2 · 1⤊ 0⤋
27%
2006-12-27 18:44:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋