Identifying Polynomials, and factoring them by grouping terms.
For Example:
Factor: 5(x+y) +w(x+y) You see you can group x+y
So it equals (x+y)(5+w) After, you group the reamaning terms.
2006-12-27 10:03:24
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answer #1
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answered by etihad 3
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Factoring by grouping is similar to grouping like terms in regular algebra.
For instance, if you have
x^2 (x + 2) - 4 (x + 2)
Then, as you can notice, we have (x + 2) in both terms. That means we can effectively "factor" out (x + 2), as if it were something like y. After all, if
(x^2)(y) - 4(y) can become
y(x^2 - 4)
Why can't
x^2 (x + 2) - 4 (x + 2) become
(x + 2) (x^2 - 4)?
That's the whole concept of grouping.
An example of when you'd have to group is here:
Factor x^3 - 4x^2 + 2x - 8.
Factor the first two terms and the second two terms.
x^2 (x - 4) + 2(x - 4)
Now, group.
(x^2 + 2) (x - 4)
2006-12-27 17:29:54
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answer #2
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answered by Puggy 7
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it mean collecting similar variables into groups for example
ab+cb+xa+xc
to factorize the above by grouping, we collect similar variable into groups as seen below;
b(a+c)+x(a+c)
that's it
2006-12-27 17:30:14
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answer #3
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answered by George 3
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identlfying patterns
2006-12-27 17:25:30
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answer #4
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answered by anastasia 4
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