(5x^4)^2(z^2)/(5z^4)
(25x^8)(z^2)/(5z^4)
(5x^8)(z^2)/(z^4)
(5x^8)/(z^2)
2006-12-27 08:54:58
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answer #1
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answered by aficionado210 2
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(5x^4)^2 z^2/5z^4 = ?
(5x^4)^2 = 25x^8. After that there are a multitude of ways of reading the expression, some of which can be simplified, some not.
2006-12-27 16:53:55
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answer #2
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answered by Helmut 7
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(5x^4)^2 z^2/5z^4 = 5^2 x^8 z^2 / (5z^4)
= 5 X^8 / z^2
2006-12-27 16:39:38
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answer #3
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answered by bozo 4
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expand remember exponent laws
(aB^c)(dB^e)=(a)(d)^(c+e)
(5)(5)^(4+4) when (5x^4)^2 is expanded
=25x^8z^2/5z^4 take out common facotr out on top and bottom
=z^2(25x^8)/z^2(5z^2) it's important to remember exponent laws when facotring out exponents z^2(z^2)=z^4 still
z^2 cancel out leaving final solution
=25x^8/5z^2 or (5x^4)^2/5z^2
2006-12-27 16:37:13
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answer #4
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answered by Zidane 3
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25x^8 1/5z^2
2006-12-27 16:39:57
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answer #5
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answered by JasonM 7
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((5x^4))^2 (z^2)
------------------- is that the expression?
(5z^4)
It then becomes (5x^8)(z^2) ((625)*(625))*(x^8)*(z^2)
-------------- = ------------------------------
625z^4 ((625))*(z^2)^2
((z^2)^2)this is another way to write z^4)
The z^2 and 625 cancel, and so, you are left with:
625x^8
--------- THAT IS THE FINAL ANSWER
z^2
2006-12-27 16:57:28
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answer #6
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answered by abcd 2
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(5x^4)^2 z^2/5z^4
25(x^8)(z^2)/5(z^4)
5(x^8)/(z^2)
2006-12-27 16:40:05
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answer #7
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answered by Tom :: Athier than Thou 6
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this is confusing. can you add another set of parenthesis?
2006-12-27 16:38:01
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answer #8
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answered by !{¤©¤}! 4
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i dunno :S
2006-12-27 16:40:52
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answer #9
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answered by ? 5
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