with working out please
2006-12-27 07:21:46 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2 + y^2 = 61
25+36=61
x=5, y=6
2(5)-7=3
2006-12-27 07:29:19 · answer #1 · answered by JM 2 · 0⤊ 2⤋
Several interesting answers already , but since you didn't say x and y had to be whole numbers or what 2x-7 = to it can only be expressed as an equasion .
First look at the x^ + y ^ =61
balance the equasion with only x on one side
x^ = 61 - y^ then
x= (61-y^)/x now apply this to the original formula 2x-7
( 2(61-y^)/x) - 7 now multiply
(122-2y^/x) - 7 is as far as you can take the equasion with your present information.
2006-12-27 15:46:16 · answer #2 · answered by thomas 7 · 0⤊ 1⤋
well, x and y would have to equal 5 and 6, but there's no way to differentiate which one is which... so the answer for 2x-7 would be either 3, or 5
2006-12-27 15:31:01 · answer #3 · answered by ensnentill 5 · 2⤊ 0⤋
x^2 + y^2 = 61..........(1)
let's assume that
2x-7=y/2...................(2)
>>>>y=4x-14
substitute into(1)
x^2+(4x-14)^2 =61
expand
x^2+(16x^2-112x+196=61
giving
17x^2-118x+135=0
using quadratic formula
x={112+or-sqrt(112^2-4*17*135)}/34
={112+or-58}/34
=5 or 27/17
whenx=5,
y=20-14=6 {from(2)}
whenx=27/17,
y=2(54/17-119/17)
= -130/17 {from(2)}
hence,solution set is
{5,6},{27/17,-130/17}
i hope that this helps
2006-12-27 16:00:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
OK!
You need to provide more info: 2x - 7 = *what*
2006-12-27 15:24:09 · answer #5 · answered by Jerry P 6 · 0⤊ 0⤋
It would help if you gave us the whole question, not just a bit of it.
2006-12-28 01:40:12 · answer #6 · answered by Martin 5 · 1⤊ 0⤋
Not enough info.
2006-12-27 15:29:10 · answer #7 · answered by Jill&Justin 5 · 0⤊ 0⤋
Do your own homework
2006-12-27 16:59:30 · answer #8 · answered by m.paley 3 · 0⤊ 0⤋
Why would you want to?
2006-12-27 15:24:34 · answer #9 · answered by Jolly Jo Jo 3 · 0⤊ 0⤋
that doesnt make sense
2006-12-27 15:47:11 · answer #10 · answered by ILBW 2 · 1⤊ 0⤋