Why is it misleading to say this is a C student?
a)one must use measures of centrtal tendancy to describe data.
b)the highest grade is a B
c)observation alone is insufficient
d)a and c
2006-12-27 06:16:40 · 8 answers · asked by ferrari 1 in Science & Mathematics ➔ Mathematics
It is not option a because the modal (=a measure of central tendency) grade is C : grades are 78=C, 79=C, 80=B, 89=B, 75=C. The modal grade is C.
Since it is not a) it can not be d).
You have to choose between b and c.
I would suggest it is not c).... I mean, what else do you have besides observation, bribery??????
I would answer b). I disagree with the statement, "a student should be evaluated on the highest grade" but it is the only one that makes sense, given the limitations. I would guess that they were expecting a) and thinking mean, but it is poorly worded.
Oh yeah, the median is also C: so the mean is B, the median is C, and the mode is C .....
2006-12-27 06:39:14 · answer #1 · answered by a_math_guy 5 · 0⤊ 0⤋
A or D...
The average of the grades is 80.2 so technically it is a B student. I would say D. You should calculate the average. Simply seeing that 3 out of 5 grades are Cs is not adequate.
Mean, meadian and mode are all measures of central tendancy. Depending on which one you use, you could wind up at a different grade. But typicallly with grades you use mean. Especially with small amounts of numbers and working with a range like grade letters. 2 of the Cs are upper C. One is a middle, there is a low B and a high B. The high B is 89 the low is 75. Looking at the data, one can almost conclude it is a B student or very close, but you can't be sure until you calculate.
2006-12-27 14:25:45 · answer #2 · answered by Duds331 5 · 0⤊ 0⤋
It's not. Throwing out the high and low and averaging the remaining gives a 79 (a C).
2006-12-27 14:26:51 · answer #3 · answered by golgy99 1 · 0⤊ 0⤋
a)one must use measures of Central tendency to describe data.
I would suggest answer (a) because it takes the whole range into consideration.
2006-12-27 14:23:01 · answer #4 · answered by Brenmore 5 · 0⤊ 0⤋
None of the above. You have insufficient data for making the projection.
2006-12-27 14:30:11 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋
Add them all up and divide by 5 to get their average!
2006-12-27 14:25:21 · answer #6 · answered by Cinnamon girl 3 · 0⤊ 0⤋
ummm d?
His average score is 80.2 so he is a B- student.
2006-12-27 14:22:33 · answer #7 · answered by E 5 · 0⤊ 0⤋
c
2006-12-27 14:24:43 · answer #8 · answered by ken s 6 · 0⤊ 0⤋