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The eyepeice of a compound light microscope has a magnification of 10x and the low-power objective and high-power objective lenses have magnifications of 10x and 30x,respectively. If the diameter of the low-power field measures 1500 micrometers, the diameter of the high-power field will measure either 4500 micrometers or 500 micrometers. Select the correct diameter and explain your answer

2006-12-27 06:05:36 · 5 answers · asked by bob 1 in Science & Mathematics Mathematics

5 answers

OK!

The field that you see in the eyepiece has the same apparent diameter, no matter what the magnification is. So, as you increase the magnification, the *actual* diameter of the object represented by that field will be smaller. That is, a smaller object will fill up the field of view more at higher magnifications. (The amoeba, blood cell, crystal, etc. "looks" bigger.) If the object takes up 20% of the field of view on low power, it will take up 60% of the field of view on high power, for example. Thus, the diameter of the high power field in your problem will be 500 um.

2006-12-27 06:16:02 · answer #1 · answered by Jerry P 6 · 0 1

A compound microscope is called a light microscope because there is a light source that shines a light up through the microscope slice so you can see it. Some older compound microscopes used a mirror which you had to angle in such a way to capture ambient light in the room. Modern compound microsopes use an electric light. These are located under the stage.

2016-03-29 08:24:33 · answer #2 · answered by Amber 4 · 0 0

I'd say 500 seems most logical because it offers you a great deal less scope than 1500. If you take a look at microscopes, the high power objectives allow you to look closely at a smaller piece of the specimen.

2006-12-27 06:16:48 · answer #3 · answered by Shurikens Rule! 2 · 1 0

Powerfield 1500

2016-12-15 14:32:56 · answer #4 · answered by Anonymous · 0 0

The answer your teacher wants is 500 um. Your apparent field of view will remain the same. If you've measured that at 1500 um at 100x, then at 300x, your apparent field of view will represent one-third the field at 100x, which would be 500 um..

2006-12-27 07:10:29 · answer #5 · answered by Anonymous · 0 1

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