After 4.00 mol of C2H4(g) and 2.50 mol of Br2(g) are placed in a sealed 1.0-L container, the reaction?

Question

C2H4(g) as it changes over time at a fixed temperature until equilibrium is reached.
2) Caulculate equilibruim concentrations
c)Calculate the percent reaction at equalilibrium

Answer 1

Ethylene or Ethene (C2H4) is the smallest possible hydrocarbon with a double bond. With a boiling point of −103.7° C, it is usually a gas. However 4 moles would usually take a volume of over 80 liters at STP.

Bromine, a liquid at room temperature (BP = 58.8 °C) would initially condense if introduced into a 1.0 liter container. With a density of 3.1028 g/cc, 2.50 moles (with a mass of almost 400 grams) would require 128.76 cc (or about 129 mL) of volume.

This would leave about 1000 - 129 = 871 mL in the sealed container for the Ethylene. The pressure at near room temperature would be over 10 atmospheres.

The reaction, adding the Bromine across the double bond of the Ethylene, is:

C2H4 + Br2 --> C2H4Br2

One mole of Bromine would react with one mole of Ethylene, so 2.5 moles of Bromine would react with 2.5 moles of Ethylene leaving 4.00 - 2.50 = 1.5 moles of Ethylene in excess. The extremely high pressure would drive the reaction almost to completion.

At equilibrium, the mixture would contain almost 2.5 moles of 1,2 Dibromoethane, about 1.5 moles of Ethylene and a trace of Bromine.

Answer 2

B, .200M. First, set up an ICE table. N2 + 3H2 <------> 2NH3 initially: (.25M) of N2....(.40M H2).....(0M NH3) substitute: -.10M of N2....-.30M........+.20M NH3 Equilibrium: (.15M N2)... .(.100M H2).....(.200M NH3) So, this tells you that at equilibrium, there will be .100M of H2. So, how do you come across the equilibrium of all 3? you may desire to apply straight forward stoichiometry. .30M H2 ( a million mol N2 / 3 mol H2) = .100M N2, so N2 differences by using .10M. through fact this is a reactant, .10M of this disappears. .30M H2 ( 2 mol NH3 / 3 mol H2) = .200M NH3, so NH3 differences by using .200M, through fact this is a product, you upload .200M. Thats why the respond is B.

Answer 3

C2H4 + Br2 --> C2H4Br2

2.5 moles Dibromoethane
1.5 moles of Ethylene

http://www.wikihow.com/Calculate-Percent-Yield