1.s^2-(64-121)=0
2.v^2-(16/49)=0
2006-12-27 02:25:21 · 5 answers · asked by baseballman1243 1 in Science & Mathematics ➔ Mathematics
sorry the first one is s^2-(64/121)=0
2006-12-27 02:26:52 · update #1
1) s^2=64/121
s=+/-8/11
2) v^2= 16/49
v=+/-4/7
2006-12-27 02:30:33 · answer #1 · answered by Maths Rocks 4 · 0⤊ 0⤋
1.
s^2=64/121
s=the square root of 64/121=8/11
2.
v^2=16/49
v= the square root of 16/49=4/7
2006-12-27 11:16:19 · answer #2 · answered by swimfastlane 1 · 0⤊ 0⤋
1. s^2-(64/121)+(64/121)=0+(64/121)
s^2 = 64/121
s = sqr(64/121)
s = sqr(64) / sqr (121)
s = 8 / 11
2. v^2 = 16/49
v = sqr (16/49)
v = 4/7
I showed all the steps for #1. 2 is the same, I just didn't show all the steps. You should.
2006-12-27 10:34:12 · answer #3 · answered by Sun and Sand 3 · 0⤊ 0⤋
1) s = 8/11 or s = -8/11
2) v = 4/7 or v = -4/7
2006-12-27 10:28:34 · answer #4 · answered by gjmb1960 7 · 0⤊ 0⤋
{s:s= - 8/11,8/11}
{v:v= - 4/7,4/7}
2006-12-27 10:32:05 · answer #5 · answered by aficionado210 2 · 0⤊ 0⤋