a man sold 2 cows for Rs3000each,gaining 20% on one and loosing 20% on the other.find the gain or loss percent

Question

calculate the gain or loss percent on the whole transaction.

Answer 1

loss of 4%
sale price of 1st cow is = 3000
profit is 20%
so, cost price is = 100*3000/(100+20)
=2500
sale price of 2nd cow is = 3000
loss is 20%
so, cost price is =100*3000/(100-20)
=3750
so total cost price of 2 cows is = 2500+3750 = 6250

sale price of 2 cows is =3000+3000 = 6000

loss is = 6250-6000
=250
percentage of loss is 100*250/6000
= 4.%

Answer 2

Purchase of two cows: 3750 +2500 = 6250
Sale of 2 cows = 3000(20% loss)+ 3000(20% profit) = 6000
Hence Loss is Rs.250/; ie loss percentage is 250x100/6000= 4%

Answer 3

Buying price of Cow 1 = Rs. 2500
Selling price of Cow 1 = Rs. 3000 (profit is Rs. 500 or 20%)

Buying price of Cow 2 = Rs. 3750
Selling price of Cow 2 = Rs. 3000 (loss is Rs. 750 or 20%)

Total buying price = 6250
Total selling price = 6000
Hence loss = Rs. 250 or 4% on the overall transaction

Answer 4

formulae to be used:-
when SP and profit % is given, CP = SP*100/100+p%
when SP and loss% is given, CP = SP*100/100-l%
when loss and CP is given, L% = L/CP*100

method to solve:
given,the SP of the 2 cows=Rs.3000 each.
consider the first cow,
SP = Rs.3000
P% = 20%
CP = 3000*100/100+20
=Rs.2500

consider the second cow,
SP = Rs.3000
L% = 20%
CP = 3000*100/100-20
= Rs.3750

now calculate total SP = 3000+3000=Rs.6000
and total CP = 2500 + 3750 = Rs.6250
here, CP > SP
therefore it is a loss.
loss = 6250 - 6000
=Rs.250
loss% = 250/6250*100
=4%
therefore the total loss = 4%

Answer 5

Purchase price of the 1st cow is = 3000 * 10/12 = Rs 2,500/-
Purchase price of the 2nd cow is= 3000 * 10/8 = Rs 3,750/-

Total purchase price of both the cows = Rs 6250/- (2500 +3750)
Total sale price of both the cows = Rs 6000/- (3000*2)
Loss on sale of the cows = Rs 250/-
%age of loss on sale of cows = 4 (250 * 100/6250)

Answer 6

Two cows were sold.
Let the cost price be x,y
1] profit of 20%
1.2x=3000
x=2500 rs
2] loss of 20%
.8y=3000
y=3750 rs
total cost
=x+y
=2500+3750
=6250rs
total sale price
=6000 rs
There is thus a loss
%loss
=[250/6250]*100
=4%

Answer 7

(4% loss on cost price of 3250Rs.)
SELLING PRICE=Rs3000each
Profit on cow-1=20%
Loss on cow-2=20%
Now, for calculating % , the base is 100, so we have to compare 3000 with 120 with 20%gain.
So,120%=Rs3000
so, 100%= ?
cost price=3000*100/120
AMOUNT=Rs.2500 for 20 % gain.
NOW, we have to compare 3000 with 80 with 20%loss.
So,80%=Rs3000
so,100%= ?
cost price=3000*100/80
AMOUNT=Rs.3750 for 20 % loss.
Now, total selling price=Rs.3000+Rs.3000=Rs.6000
Now, total cost price=Rs.2500+Rs.3750=Rs.6250
So, total loss on both cow=Rs.6250-Rs.6000
So, total loss on both cow=Rs.250.
So, %loss on selling of both cow at Rs.6000 and at a cost price of 6250.
=250*100/6250
=4 % loss.

Answer 8

(4% loss on cost price of 3250Rs.)
SELLING PRICE=Rs3000each
Profit on cow-1=20%
Loss on cow-2=20%
Now, for calculating % , the base is 100, so we have to compare 3000 with 120 with 20%gain.
So,120%=Rs3000
so, 100%= ?
cost price=3000*100/120
AMOUNT=Rs.2500 for 20 % gain.
NOW, we have to compare 3000 with 80 with 20%loss.
So,80%=Rs3000
so,100%= ?
cost price=3000*100/80
AMOUNT=Rs.3750 for 20 % loss.
Now, total selling price=Rs.3000+Rs.3000=Rs.6000
Now, total cost price=Rs.2500+Rs.3750=Rs.6250
So, total loss on both cow=Rs.6250-Rs.6000
So, total loss on both cow=Rs.250.
So, %loss on selling of both cow at Rs.6000 and at a cost price of 6250.
=250*100/6250
=4 % loss.

Answer 9

If he gained 20% on one then he bought it for 2500

3000 / 1.2 = 2500

If he lost 20% on the other, he bought that one for 3600

3000 * 1.2 = 3600

So he paid 6100 for both and got 6000 back, loosing 100.

100 / 6000 = 1.66% loss

Answer 10

(20/10)^2 that is 4 percent.....loss of course...