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9 answers

Subtract 5x and add 2 from both sides:
x^2-7x+2=0

Here's the quadratic formula:
x=-b±√b^2-4ac/2a
a=1,b=-7,c=2
x=-(-7)±√(-7)^2-4(1*2)/2(1)
x=7±√49-4(2)/2
x=7±√49-8/2
x=(7±√41)/2

2006-12-27 07:43:35 · answer #1 · answered by Anonymous · 4 0

nicely the formula for fixing an quadratic equation is -b + - the sq. root of b squared + 4 x A rewrite the equation like this 8x + x -5 8x=A x=b and -5 is c -x + and minus x to the 2nd skill + 4 x 8 x -5 be squared equals 8x8 it quite is sixty 4 + 4 x a x -5 a good 20 x X 20 x a million is 20 the sq. root of 20 is 4.40 seven + -8 = -3.fifty 3 then minus is is 11.fifty 3 so which you have 2 solutions 11.fifty 3 constructive and -3.fifty 3 detrimental quantity thats how i do quadratic equations I dont know if its precise this is mandatory to to learn with somebody who's conscious extra with regard to the stuff like a math instructor

2016-11-23 19:22:36 · answer #2 · answered by Anonymous · 0 0

x² -2x = 5x - 2

x² - 2x - 5x = 5x - 2 - 5x

x² - 7x = - 2

x² - 7x + 2 = - 2 + 2

x² - 7x + 2

- - - - - - - - - -

a = 1

b = - 7

c = 2

- - - - - - - - - - --

Quadratic formula

x = - b ± √b² - 4ac / 2a

x = - ( - 7 ) ± √(- 7)² - 4(1)(2) / 2(1)

x = 7 ± √49 - 8 / 2

x = 7 ± √41 / 2

x = 3.5 ± 6.403124237 / 2

x = 3.5 ± 3.201562119

- - - - - - - - - - - - - - - - -

Solving for +

3.5 + 3.201562119 =

6.701562119

- - - - - - - --

Solving for -

3.5- 3.201562119 =

0.298437881

- - - - - - - -s-

2006-12-27 05:51:30 · answer #3 · answered by SAMUEL D 7 · 3 1

If x^2 - 2x = 5x - 2
then x^2 - 7x + 2 = 0
(subtract 5x from both sides, and add two to both sides)
so x = [7 +/- sqrt(49 - 40)]/2
= [7 +/- 3]/2
= 10/2 or 4/2
= 5 or 2.

2006-12-27 00:19:38 · answer #4 · answered by Spell Check! 3 · 0 4

x^2 - 7x + 2 =0
x= [7+(49-8)^1/2]/ 2 , x= [7-(49-8)^1/2]/ 2

2006-12-27 00:17:19 · answer #5 · answered by bh 2 · 3 0

x^2 - 2x = 5x - 2
x^2 - 7x + 2 = 0

x = [-(-7) ± √((-7)^2 - 4(1)(2))] / 2(1)
x = [7 ± √(41)] / 2
x ~ 0.3, 6.7

2006-12-27 00:15:23 · answer #6 · answered by bayou64 4 · 3 0

x^2-7x+2=0
D=b^2-4ac for eq of form ax^2+bx+c=0
D=(-7)^2-4(1)(2)
=41
x=(7+41^1\2)/2 or (7-41^1\2)\2

2006-12-27 00:23:51 · answer #7 · answered by doctor 5 · 3 0

a=1
b=-7
c=2

use quadratic formula to find the roots

2006-12-27 00:18:40 · answer #8 · answered by iyiogrenci 6 · 3 1

x^2 -7x+2=0
x=[7+/-sqrt41]/2

2006-12-27 02:35:23 · answer #9 · answered by Maths Rocks 4 · 3 0

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