quadratic equation: solve using the square root property: (x+6)^2 = 121?

Answer 1

(x + 6)^2 = 121

Note that whenever you take the square root of both sides of a function, you ALWAYS have to add a "plus or minus" on one of the sides. I'll denote "plus or minus" as "+/-"

x + 6 = +/- 11

Moving the 6 to the right hand side, we get

x = -6 +/- 11, which means we get two solutions:

x = {-6 + 11, -6 - 11}, OR
x = {5, -17}

Answer 2

(x + 6)² = 121

Taking the square root on both sides,

x + 6 = 11; thus x = 5.

This is the obvious answer; but, in extracting the square root of 121, -11 is also a valid result. In this case, x = -17.

Answer 3

Multiply the two sides through -a million to get (x-10)^2 = 121, so the two x-10 = 11 or -11. in the 1st difficulty, x = 21, and in the 2d, x = -a million, the two strategies arrived at through including 10 to the two sides.

Answer 4

(x + 6)^2 = 121
impiles (x + 6) = sqrt (121)
implies (x + 6) = 11 or (x + 6) = -11
implies x = 11-6 = 5 or x = -11-6 = -17
Thus x = 5 or x = -17
x = {5, -17}

Answer 5

x+6=+ 11 , x+6= -11
x=5 , x= -17

Answer 6

take square root of both sides
x+6=11
x=11-6=5
or

x+6=-11
x=-11-6=-17

delta is positive.
there are two distinct roots

Answer 7

√(x+6)^2=√121
x+6=11
x=±11-6
x=11-6 or -11-6
x=5 or -17

Check:
(5+6)^2=121
11^2=121
121=121

(-17+6)^2=121
(-11)^2=121
121=121