any way to simplify this equation log(a+1)= 5?

Question

please help me

Answer 1

log (a+1)=5 means this: 10^5=(a+1)

So a=10^5-1=100,000-1=99,999

a=99,999

Answer 2

If the base number of the log is c, then log(a+1) = 5 means :

a + 1 = c^5.

For example, we take c = 10 (usually, this is the case)
Then a+1 = 100,000
Therefore a = 99,999

Answer 3

a = 4

Answer 4

log A = B is equal to 10 ^ B = A
(A log without a base has a base of 10)

so, log (a+1) = 5 is equal to 10 ^ 5 = (a+1)

10 ^ 5 - 1 = a
100,000 - 1 = a
99, 999 = a

done.,

Answer 5

Remember that log means the exponent of a base 10 expression.
So:

(a+1)= 10^5

a= 10^5 -1

a=99,999

Answer 6

log(a+1) means it is to the base 10.

It would be written ln instead of log for the base to be any number c i.e. ln(a+1) = 5

Here log(a+1) = 5
a+1 = 10^5
a+1 = 100,000
a = 100,000 - 1
a = 99,999

Answer 7

2(2sinQcosQ) = a million sin2Q = a million/2 2Q = 30deg Q = 15deg loga8 = 3loga2 = 3x a^logax = x (the log cancels out) change interior the 2d equation (3x)(x) = 12 4x = 12 x = 3 we are not done yet, remedy for a loga2 = 3 a^3 = 2 a = the cubed root of (2)

Answer 8

5 = log 10^5

(Since it says log and not ln, I am assuming that you are asking about logarithms base 10.)

So log (a + 1) = log 10^5.
10^5 = 100,000.
Take the antilog of both sides, gives
a + 1 = 100,000, so
a = 99,999.

Cheers!

Answer 9

It actually depends on the base of log. These are 10 or 'e' usually.
(e=2.72)
if base is 10
then a+1=10^5
hence a = 99999
but if base is e then
a+1=e^5
a= 147.4
and hence u can solve it for any base.

Answer 10

log(a+1)=5 <=> log(a+1)=5*log10 <=>log(a+1)=log10^5 <=> a+1=10^5 <=> a=99.999