A weather balloon is filled with 1.0 liter of helium at 23 degrees C and 1.0 atm. What volume does the balloon have when it has risen to a point in the atmosphere where the pressure is 220 torr and the temperature is -31degrees C
2006-12-26 21:49:24 · 4 answers · asked by rishelly2528 1 in Science & Mathematics ➔ Chemistry
1 atm = 760 torr
you must convert temperature to Kelvins
23+ 273.15 = 296.15K
273.15 - 31 = 242.15K
PV/T = PV/T
760*1L/296.15 = 220*X/242.15
X = 760*242.15/(220*296.15)
sorry, no calculator
***the combined gas law is a god-send.
2006-12-26 22:00:38 · answer #1 · answered by beanie_boy_007 3 · 0⤊ 0⤋
Because of the pressure change, V = 760/220 x 1 =3.45 litres.
Because of the temp change (in deg K), V = 3.45 x 242/296 = 2.82 litres.
2006-12-27 07:52:24 · answer #2 · answered by JJ 7 · 0⤊ 0⤋
(P1)(V1)/(T1) = (P2)(V2)/(T2)
HENCE..
(1 *1)/296 = (V)*(220/760)/242
760torr = 1atm ,hence
220 torr = (220/760) atm
so, V = 2.82 L
2006-12-27 06:06:04 · answer #3 · answered by skr 2 · 0⤊ 0⤋
(P1/V1)/T1 = (P2/V2)/T2
off you go.
2006-12-27 05:53:07 · answer #4 · answered by Anonymous · 2⤊ 0⤋