2006-12-26 18:31:51 · 20 answers · asked by rohini s 1 in Science & Mathematics ➔ Mathematics
d = 70cm
r = 35cm
circumference = 2x22/7x35
= 220cm
220 cm --------- 1 revolution
1 cm--------------1/220 revolution
110 cm------------1/220x110 revolution
=1/2 revolution
2006-12-26 18:54:45 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1/2 times
2006-12-27 01:11:56 · answer #2 · answered by MUDIT 2 · 0⤊ 0⤋
The diameter(d)=70 Hence the radius(r)=70/2=35cm
The circumference(C)=2*22/7*35
=220cm
No. of revolutions = distance/C
=110/220
=0.5
Therefore the wheel revolves 0.5 times
2006-12-26 18:43:36 · answer #3 · answered by Nimmi 2 · 0⤊ 0⤋
If the diameter is 70cm, the circumference is 70cm(pi) = 70pi cm, or roughly 217cm.
So, to travel 110cm, it's going to take 110/70pi revolutions, or roughly 1/2 revolution.
2006-12-26 18:35:50 · answer #4 · answered by Jim Burnell 6 · 0⤊ 0⤋
If the diameter is 70cm, then circumference is (pi)d = 70pi cm
So, to travel 110cm, it's going to take 110/70pi revolutions, or roughly 1/2 revolution.
2006-12-26 20:17:50 · answer #5 · answered by Kinu Sharma 2 · 0⤊ 0⤋
one round is 70cm so the wheel has to turn 1/4/7 round to cover 110cm or 1.57142 rounds.
2006-12-26 18:50:44 · answer #6 · answered by tckg_32 1 · 0⤊ 0⤋
Well first you must find the circumference which is (pi)*(diameter) so, 3.14 times 70 = 219.80cm
Then, you set it up
1 x (the x should be over the 110)
----- = ------
219.8 110
Cross multiply and you get 110=219.8x
solve for x and x=0.50045
So the wheel must revolve approximately half-way around to cover that distance.
2006-12-26 18:40:12 · answer #7 · answered by Lori S 2 · 0⤊ 0⤋
0.5 times or 1/2 revolution
calculation:
diamiter = d
= 70cm
distance = x
= 110cm
perimeter of the wheel = 2*pi*(d/2) cm
= 2*pi*(70/2) cm
= 219.91 cm
where pi = 3.1415926535897932384626433832795
therefore revolution required to cover the distance is 110/219.91 or 0.5 times
2006-12-26 19:10:51 · answer #8 · answered by Shahidur R 2 · 0⤊ 0⤋
Diameter of wheel d = 70 cm
Number of revolutions to cover distance of 110 cm = n
n = 110/(70π) = 11/(7π) = 0.5002 revolutions
2006-12-26 18:55:18 · answer #9 · answered by Northstar 7 · 0⤊ 0⤋
given:d=70 cms.
---->r=d/2 = 35cms.
perimeter of wheel=2*22/7*35
=220cms
it means the wheel travels a distance of 220 cm for every revolution.
but distance to travel=110cms
therefore distance is half.
so wheel should undergo half a revolution.
2006-12-27 02:38:33 · answer #10 · answered by shreya i 2 · 0⤊ 0⤋
For a circle the length of distance covered in 1 revolution is = circumference = 2*3.142*radius
In this case circumference = 2*3.142*(70/2)=219.94 cm
Number of revolutions = Distance/Circumference
=110/219.94=0.5 revolutions
Answer is the wheel will take 0.5 revolutions
2006-12-26 18:56:59 · answer #11 · answered by Anonymous · 0⤊ 0⤋