if a person rolls two dice, what is the probability of getting a sum of 6, double, a sum of 7 or 11?

Question

...be sure your answer is CORRECT...
and continuation... of my question above

d)A sum of greater than 9
e)A sum less than or equal to 4

Answer 1

a. 5/36 for sum of 6
b.1/6 for a double (happens 6 of 36 times)
c.2/9 for 7 or 11 (happens 8/36 times)
d.1/6 (happens 6 of 36 times)
e. 1/6

Here's how you do it. Write the numbers 1-6 across the top of a paper and 1-6 down the left side. Like this:
1 2 3 4 5 6
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12

The numbers under all the sums.

Answer 2

Just figure out the ways each of these totals can be obtained and divide by 36: for example, to get exactly 6, you can get

1 and 5
2 and 4
3 and 3
4 and 2
5 and 1

for a total of 5 ways. Therefore the probability of getting exactly 6 from two dice is 5/36. The others are figured the same way.

Answer 3

Probability of sum of 6 = 5/36 [ (1,5) , (2,4) , (3,3) , (4,2) , (5,1) ]
For sum 7 or 11, calculate sum 7's and sum 11's probability and subtract the number of common events in the two.
Th others are done in same way as first. Dont know what u mean by double. Hope this solves your problem.
PS: Are in u in class 11 in CBSE syllabus? I am and i gotta study these such as a sum of 7 or 11. If u are u should know the formula else check below for it:
P(A or B) = P(A u B) = P(A) + P(B) - P(A i B).
u means union in sets and i stands for intersection - the common events.

Answer 4

probability is 1/6 that the sum is greater than 9

probability is 1/6 that the sum is less than or equal to 4