factor completely 128 x squre -200?

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factor completely 128 x squre -200?

2006-12-26 09:58:03 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

5 answers

128x² - 200 = 8(16x² - 25) = 8(4x - 5)(4x + 5)

2006-12-26 10:01:14 · answer #1 · answered by Northstar 7 · 1⤊ 0⤋

128x^2 - 200

Both are divisible by 4.

8(16x^2 - 25)

Now, we have a difference of squares. Factor like was done in the last question.

8(4x - 5) (4x + 5)

2006-12-26 09:59:53 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋

128x^2-200
8(16x^2-25)
8(4x-5)(4x+5)

2006-12-26 10:25:48 · answer #3 · answered by mu_do_in 3 · 0⤊ 0⤋

4(16x^2-25)
=4(4x+5)(4x-5)

2006-12-26 10:00:55 · answer #4 · answered by raj 7 · 0⤊ 1⤋

8(4x+5)(4x-5)

2006-12-27 10:42:06 · answer #5 · answered by etihad 3 · 0⤊ 0⤋