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7√2(3√6+8√3)

2006-12-26 08:13:35 · 7 answers · asked by styles4u 4 in Science & Mathematics Mathematics

7 answers

Remember that when we multiply two radicals, we can multiply their insides; for example, sqrt(7) times sqrt(2) = sqrt(14).

First, we distribute. I'll just type out all of the multiplication to make things clear.

[7sqrt(2)][3sqrt(6)] + [7sqrt(2)][8sqrt(3)]

What we do is multiply the numbers, and then multiply the insides of the square roots to get one square root.

21sqrt(12) + 56sqrt(6)

We can simplify sqrt(12) into sqrt(4 x 3) = sqrt(4)sqrt(3) =
2sqrt(3).

21 [2sqrt(3)] + 56sqrt(6)
42sqrt(3) + 56sqrt(6)

It doesn't get much simpler than this, so we leave this expression as is, since there's nothing more to reduce.

2006-12-26 08:18:12 · answer #1 · answered by Puggy 7 · 2 0

First: use distribution > take the outside term and multiply it by the inside terms:

(7 V`2)(3 V`6) + (7 V`2)(8 V`3)

21 V`18 + 56 V`6

Second: simplify the numbers in the radicals, if possible:

21 V`(2*3*3) + 56 V`6

Third: you have a set of two 3's, take one 3 out:

21(3) V`2 + 56 V`6

63 V`2 + 56 V`6

2006-12-26 09:18:32 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0 0

7√2(3√6 + 8√3) = (7*3)(√(2*6)) + (7*8)(√(2*3))
= 21√12 + 56√6 = 21√(4*3) + 56√6
= 21√(2²*3) + 56√6 = 2*21√3 + 56√6
= 42√3 + 56√6

2006-12-26 09:40:27 · answer #3 · answered by Northstar 7 · 0 0

i'm no longer precisely constructive what ur guidelines are asserting yet while u simplify the 1st subject the respond is x-6/x+5 , the 2nd subject is x+2/x-a million, and that i do no longer think of the final you could nicely be simplified to any extent further. multiply all 3 problems at the same time and u get: x^2-4x-12 / x^2+4-5

2016-11-23 18:17:13 · answer #4 · answered by Anonymous · 0 0

(7*3)√12+(7*8)√6=
21√4*3+56√6=
(21*2)√3+56√6=
42√3+56√6

2006-12-26 09:27:47 · answer #5 · answered by Anonymous · 0 0

hmm simply solve the brackets first ... Always follow the BEDMAS Rule.. (Brackets, Exponents, Divide, Multiply, Add, Subtract)... In accordance to orders of operation...
**take square root of 6 and multiply by 3
**take square root of 3 and multiply by 8
**Add the both values(frm above) and you should get around 21.2
**therefore: 7√2(21.2); take square root of 2 and multiply by 7; and u get 9.9
**therefore: 9.9(21.2) = 209.92

Good Luck!!

2006-12-26 08:26:20 · answer #6 · answered by Anonymous · 0 0

7rt2*3rt6+7rt2*8rt3
=21rt12+56rt6
=42rt3+56rt6

2006-12-26 08:25:03 · answer #7 · answered by raj 7 · 1 0

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