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3√64a^18b^12

2006-12-26 08:02:52 · 3 answers · asked by styles4u 4 in Science & Mathematics Mathematics

3 answers

64=4^3
a^18=(a^6)^3
and b^12=(b^4)^3

so 64(a^18)(b^12)=(4(a^6)(b^4))^3

so it's cube root is 4(a^6)(b^4)

2006-12-26 10:52:13 · answer #1 · answered by Max S 2 · 0 0

I assume you mean

(64 a^18 b^12)^(1/3)

Taking something to the (1/3) power is the same as taking the cube root.

To solve this, all you have to do is take the cube root of each term inside; first the 64, then the a^(18), and then b^(12)

To take the cube root of 64, all you have to do is know that 64 is equal to 4 x 4 x 4; 64 is already a perfect cube. So the answer is 4.

When taking the cube root of variables to powers, all you have to do is divide the power by 3. For a^(18), dividing the power by 3 yields a^6. The same thing goes for b^(12).

Therefore,

(64 a^18 b^12)^(1/3) = 4(a^6)(b^4)

2006-12-26 16:25:25 · answer #2 · answered by Puggy 7 · 0 0

3√64a^18b^12
4^3=64
(a^6)^3=a^18
(b^2)^3=b^12 so
3√64a^18b^12 = 4a^3b^2

2006-12-26 17:43:54 · answer #3 · answered by mu_do_in 3 · 0 0

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