Math Problem 1?

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Give an equation for the following:

Suppose that w varies directly as z^2 and inversely as xy. When w = 10, x = 15, y = 2, and z = 5. Find z when w = 2, x = 8, and y = 27.

2006-12-26 07:40:57 · 3 answers · asked by Lawanna D 1 in Science & Mathematics ➔ Mathematics

3 answers

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2006-12-26 07:42:29 · answer #1 · answered by Hi 7 · 0⤊ 1⤋

There is a constant C such that w = C z^2 / xy.
One has 10 = C 25 / 30, so that C = 12. Hence 2 = 12 z^2 / 8 * 27, that is z^2 = 8 * 27 / 6 = 36. so z =6.

2006-12-26 15:47:31 · answer #2 · answered by gianlino 7 · 0⤊ 0⤋

z is 1

2006-12-26 15:44:31 · answer #3 · answered by T&M's Mom 2 · 0⤊ 1⤋