2006-12-26 06:21:01 · 3 answers · asked by sharonklaus8567 2 in Computers & Internet ➔ Computer Networking
240 is incorrect. It should be...
SN 1 - 192.168.128.0 (IP's = .1 to .30)
SN 2 - 192.168.128.32 (IP's = .33 to .62)
SN 3 - 192.168.128.64 (IP's = .65 to .94)
SN 4 - 192.168.128.96 (IP's = .97 to .126)
SN 5 - 192.168.128.128 (IP's = .129 to .158)
SN 6 - 192.168.128.160 (IP's = .161 to .190)
SN 7 - 192.168.128.192 (IP's = .193 to .222)
SN 8 - 192.168.128.224 (IP's = .225 to .254)
All with a subnet mask of 255.255.255.224
2006-12-26 06:34:37 · answer #1 · answered by The Psycho 6 · 1⤊ 0⤋
http://www.subnet-calculator.com/cidr.php
2006-12-26 14:28:45 · answer #2 · answered by ninesunz 3 · 1⤊ 1⤋
mask needed : 255.255.255.240
192.168.128.0--first sub
192.168.128.31--1st broadcast
192.168.128.32-2nd
192.168.128.63-2nd broadcast
etc
2006-12-26 14:26:20 · answer #3 · answered by holla 2 · 0⤊ 1⤋