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first person to get it right gets the 10 points and there is an EXACT ANSWER i am looking for.
GL and have fun...and more ideas for questions are greatly appreciated through mail..
xoxox

2006-12-26 05:10:59 · 9 answers · asked by KatastropheGirl™ 3 in Science & Mathematics Other - Science

9 answers

9.8 m/s/s
32 ft/s/s
1 G
Just enough to keep me from falling off.

2006-12-26 05:14:23 · answer #1 · answered by Crazy Malamute 3 · 0 0

The gravitational pull or (g) on earth is of
-9.98m/s^2. Or minus 9.98 meters per segonds square! Since gravity has an initial velocity which is different from its final velocity it is defined in meters per segonds square it is an acceleration or (a)
Of course the closer you get to any center of a mass the stronger the gravitational pull is, altough the difference in the gravitationnal pull on Mount Everest and the deepest pit on earth exists it is still around -9.98m/s^2, the variation is not that big.

2006-12-26 13:45:13 · answer #2 · answered by ? 2 · 0 0

There is no EXACT VALUE for gravity at any given point on the surface of the earth. It may seem odd but gravity is weaker on the top of mount everest (less than 9.8) and it is much greater (more than 9.8) in the bottom of the grand canyon

Using newton's law of universal gravitation
g = G(M/R²)
g= gravitational field strength
G= newton's famous gravitational constant (6.67x10^-11)
R=radius of the object (in this case earth)
M=mass (of the earth in this case)

if we plug in
( I obtained these "exact values" for the mass and radius of the earth from the wiki)
M=5.9742×10^24 kg
R=6,370998.685023 m
G=6.67x10^-11
we get 9.817266048m/s²

also on wiki the accepted exact value for gravity at sea level is 9.80665 m/s²

2006-12-26 13:27:45 · answer #3 · answered by Anonymous · 0 0

Your question:

who knows the force of gravity on the face of earth.?

My answer, the right one I ight add is:

Me.

I may not get your 10 points, but

TFTP

2006-12-26 13:20:27 · answer #4 · answered by Anonymous · 0 0

The gravity depends upon latitude by the formula :
g=9.8-(1-R*w^2*cos^2l );
where g is value of gravity on the particular value of latitude,R is radius of earth (in meters),w is angular velocity of earth,l is value of latitude where gravity is to be found.

2006-12-26 16:08:35 · answer #5 · answered by miinii 3 · 0 0

It depends on the latitude of the position you're measuring from. It averages out at about 9.8 ms^-2

2006-12-26 13:35:58 · answer #6 · answered by The Yeti 3 · 0 0

gravity has a pull of 9.8 m/s to the center of the earth (down)

2006-12-26 13:13:34 · answer #7 · answered by Max 2 · 0 0

9.806 meters per second

OR

32.18 feet per second

(this is at sea level, which is universally assumed as the face of the earth)

2006-12-26 13:22:48 · answer #8 · answered by Tarvold 3 · 0 0

Yes, it is 1g

2006-12-26 13:13:51 · answer #9 · answered by Anonymous · 0 1

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