what is an expression for twice the sum of s and t decreased by t?

Answer 1

2(s+t)-t
or
2s+t

Answer 2

The sum of s and t:

(s + t)

Twice:

2(s + t)

Decreased by t:

2(s + t) - t

And yes, as others are pointing out:

2(s + t) - t = 2s + 2t - t = 2s + t

But your question doesn't ask for simplification, so personally, I'd stick with 2(s + t) - t.

Answer 3

[2(s+t)]-t

To do this, you must consider the problem. First, since you are asking for twice the sum of s and t, write s + t in parenthesis. Since, according to the question, (s + t) is multiplied by two, you have to add a 2. Then, you put the whole thing in brackets and subtract t.

Answer 4

2(s+t)-t

Answer 5

if you mean 2*(s + t) - t
the answer is 2s + t

if you mean 2*((s + t) - t)
the answer is 2s

one needs to be very exact and explicit when stating a problem with words

Answer 6

2(s+t)-t, I think. It's been a while since I took an algebra class.

Answer 7

2(s+t)-t
=2s+t

Answer 8

2(s+t)-t

simplified

2s+2t-t

or

2s+t

Answer 9

2(s+t) - t

2s + 2t - t

2s + t