3x-5y=y-mx
2006-12-26 04:11:38 · 15 answers · asked by kieran_kai_jay 1 in Science & Mathematics ➔ Mathematics
3x - 5y = y - mx
x (3 + m) = 6y
x = 6y / (m + 3)
is this what you wanted?
2006-12-26 04:14:05 · answer #1 · answered by Crazy Malamute 3 · 0⤊ 1⤋
3x - 5y = y - mx
add mx+5y to both sides of the equation
3x - 5y + mx + 5y = y - mx + mx + 5y
Rearrange in case the next bit isn't obvious
3x+ mx + 5y - 5y = y + 5y + mx - mx
Add the terms (cancelling out some of them)
(3 + m) x = 6y
Divide both sides by (3 + m) [only allowed if m is not equal to -3, division by zero is barred]
x = 6y/(3 + m)
2006-12-26 12:17:57 · answer #2 · answered by Dr Bob UK 3 · 0⤊ 1⤋
Put all the x's on one side of the equation and all the y's on the other. Then factorise out the x's so x is on its own and divide the y side by the factor multiplying the x's.
3x - 5y = y - mx
3x + mx = 6y
x(3+m) = 6y
x = 6y/(3+m)
2006-12-27 05:15:03 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1) Take the x's together on the left and the y's on the right:
3x+mx=y+5y.......so 3x+mx=6y Then factorise the left:
x(3+m) = 6y
so x = 6y/(3+m)
2006-12-26 14:03:02 · answer #4 · answered by Anonymous · 0⤊ 1⤋
I'm guessing you want to solve for x? If so, I would do...
3x+mx=y+5y
(3+m)x=6y
x=6y/(3+m)
2006-12-26 12:15:02 · answer #5 · answered by Stargazing 1 · 0⤊ 1⤋
3x-5y=y-mx
3x + mx = y + 5y
x (3 + m) = 6y
x = 6y / (3 + m)
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2006-12-26 13:06:52 · answer #6 · answered by aeiou 7 · 0⤊ 1⤋
X=6y/(3+m)
2006-12-26 12:14:46 · answer #7 · answered by Oldbeard 3 · 0⤊ 1⤋
3x-5y=y-mx
=3x+mx=6y
=x(3+m)=6y
=x=6y/3+m
hope it helps!!
2006-12-26 12:49:45 · answer #8 · answered by Kwunbob 2 · 0⤊ 1⤋
3x-5y=y-mx
3x+mx=6y
3x=6y-mx
x=(6y-mx)/3
2006-12-26 12:18:19 · answer #9 · answered by Anonymous · 0⤊ 1⤋
3x-5y=y-mx
3x+mx=y+5y
x(3+m)=6y
x=6y/(3+m)
2006-12-26 12:15:16 · answer #10 · answered by Gayan K 1 · 0⤊ 1⤋