English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2006-12-26 03:08:04 · 12 answers · asked by blahblah 2 in Science & Mathematics Mathematics

How did it become subtraction?

2006-12-26 03:18:19 · update #1

12 answers

3(2x + 5) = x +35

6x + 15 = x + 35

6x - x = 35 - 15

5x = 20

x = 20 / 5

x = 4

Whenever the terms are transposed from on side of the equal to sign, the signs are reversed.
+ becomes -
* becomes /
log becomes antilog
and so on for everything

2006-12-26 03:18:53 · answer #1 · answered by Anonymous · 2 1

3(2x + 5) = x + 35

Your first step is to distribute that 3 over the brackets; that is, multiply 3 by each term.

3(2x) + 3(5) = x + 35

Multiply them out, getting

6x + 15 = x + 35

Now, move all x terms to the left hand side, and move everything else to the right hand side. In an equation, whenever you move something from one side to the other, the sign changes. In our case, the +15 would change to -15 when moved to the right hand side, and the +x will change into a -x when moved to the left hand side.

6x - x = 35 - 15

Simplify

5x = 20

And now, divide both sides by 5. Remember that we want to isolate the x, which is why we do that.

5x/5 = 20/5
x = 4

2006-12-26 03:20:47 · answer #2 · answered by Puggy 7 · 1 0

First, 3(2x+5) = 6x + 15. So,
6x + 15 = x +35
Making the right side =0:
6x + 15 - x -35 = 0
Simplifying:
5x -20 =0
Divide both sides by 5:
x - 4 = 0 So,
x = +4

2006-12-26 03:14:12 · answer #3 · answered by Renaud 3 · 0 1

3(2x + 5) = x + 35

multiply

6x + 15 = x + 35

transpose x to one side and numbers to other side

6 x - x = 35 - 15

5 x = 20

x = 4

2006-12-26 03:50:08 · answer #4 · answered by David C 2 · 1 0

*Use distribution:

3(2x) + 3(5) = x + 35

6x + 15 = x + 35

First: solve for "x" and keep it on one side (left) > subtract 15 from both sides: opposite side means opposite sign:

6x + 15 - 15 = x + 35 - 15
6x = x + 20

Second: subtract x from both sides:

6x - x = x - x + 20
5x = 20

Third: divide both sides by 5:

5x/5 = 20/5
x = 4

2006-12-26 13:04:18 · answer #5 · answered by ♪♥Annie♥♪ 6 · 0 0

3(2x+5)=x+35
6x+15=x+35 (You multiply 3 with the bracket)
6x-x=35-15 (You group like terms together)
5x=20
x=20/5
x=4

2006-12-26 03:11:20 · answer #6 · answered by HsNWarsi 2 · 3 0

3(2x+5) = x+35
by opening the bracket we get,6x+15=x+35
x terms on one side n numbers on other side
6x-x=35-15(when we take a no. on other side its sign changes)
5x=20
x=20/5
x=4

2006-12-26 03:21:35 · answer #7 · answered by Anonymous · 1 0

okay, first you distribute. you get 6x+15=x+35. you wnat to comnine like terms, but since they are on teh opposite sides, you move htem over. so you move the fifteen over by subtracting fifteen from both sides. that way you get 6x=x+20. you then move over the x to the other side and get 5x=20. you then want to get x by itself so you divide both sides by five and you get

x=4.

2006-12-26 03:23:44 · answer #8 · answered by blah 4 · 0 0

3(2x+5)=x+35
6x+15=x+35
6x-x=35-15
5x=20
x=20/5
x=4

2006-12-26 03:13:40 · answer #9 · answered by Gayan K 1 · 1 0

3(2x+5)=x+35
6x+15=x+35
6x+15-x=35
5x+15=35
5x=35-15
5x=20
x=4

2006-12-26 06:44:23 · answer #10 · answered by Anonymous · 0 0

fedest.com, questions and answers