give me the sequences not how many
2006-12-26 01:16:41 · 12 answers · asked by Anonymous in Education & Reference ➔ Homework Help
This is a true Boxing day question...I take it you're bored!!
2006-12-26 01:22:18 · answer #1 · answered by georgiebuzz 2 · 0⤊ 2⤋
If you want sequences with no numbers repeated then the number of different sequences is 10*9*8*7 = 5040. If digits being repeated is allowed then the answer is 10^4 = 10000. As suggested elsewhere, I doubt if you will get anybody to list them for you, although it would be relatively easy to write a program in something like QBASIC to list the numbers for you.
2006-12-26 02:55:00 · answer #2 · answered by Paul B 5 · 1⤊ 0⤋
If you can repeat digits, then you have 9 choices for the first position (thousands place), 10 for the second place, 10 for the third place and 10 for the fourth place. You only have 9 for the first place because you cannot use 0.
Therefore, 9 * 10 * 10 * 10 = 9000 number sequences.
If you cannot repeat digits, then 9 choices for the first position, 9 for the second, 8 for the third and 7 for the fourth.
So, 9 * 9 * 8 * 7 = 4536 number sequences.
2006-12-26 11:19:51 · answer #3 · answered by LARRY R 4 · 0⤊ 0⤋
5040 different sequences -- no one will type them all out for you. (Solution is 10*9*8*7=5040)
2006-12-26 01:22:37 · answer #4 · answered by shanb 2 · 1⤊ 1⤋
um...10to power of 10... 10x10x10x10x10x10x10x10x10x10=10,000,000,000 times 4.have fun figuring it out... 40,000,000,000
2006-12-26 02:15:07 · answer #5 · answered by Shmily P 3 · 0⤊ 1⤋
Lets discuss payment first - 10pts just isn't going to cut it.
Good Luck!!! ;-)
2006-12-26 01:35:33 · answer #6 · answered by Anonymous · 0⤊ 2⤋
Good Qus.
2006-12-26 01:27:32 · answer #7 · answered by Anonymous · 0⤊ 2⤋
I've no desire to type out 5,040 permutations for you!
2006-12-26 01:49:10 · answer #8 · answered by cheekbones3 3 · 0⤊ 1⤋
bah my math flawed >.<
evereyone else is right, i wasnt o.0
2006-12-26 01:19:53 · answer #9 · answered by Dashes 6 · 0⤊ 2⤋
I've got 3 so far.
2006-12-26 01:18:07 · answer #10 · answered by Zecca 5 · 0⤊ 3⤋