If you make grids like the following you will see there is only one formula that will go through (3,2)
Y-2x+1
X Y
-3 -5
-2 -3
-1 -1
0 1
1 3
2 5
3 7
Y=2X-4
X Y
-3 -10
-2 -8
-1 -6
0 -4
1 -2
2 0
3 2
You can see that the formula Y=2x-4 is the only one that fits the requirements.
2006-12-25 17:18:39
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answer #1
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answered by The Answer Man 5
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I'll show you how to do the problem:
so the equation to the problem is y=mx+b; it has to go through the points (3,2); thus x=3, y=2
you need to find "b":
y=mx+b
y=2x+b (plug in M because it is given to you)
2=2(3)+b (plug in the points because they want it to go through those)
2=6+b (multiply 3 and 2, then bring 6 to the other side by substracting it from both sides)
thus, b= -4
then you put it back into the original equation y=mx+b
y=2x-4 so the right answer is R.
I hope that helps!
2006-12-26 01:22:35
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answer #2
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answered by Quixotic 3
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For any straight line, the equation is y=mx+c, where m is the gradient(slope) and c is the y-intercept(the pt whr the line touches the y-axis).
Since we know that y=2x+c, all we need to do is substitute the point (3,2) into it.
2=2(3)+c
c=2-6= -4
Therefore, the equation of the line is y=2x-4. Ans: R
2006-12-26 03:19:29
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answer #3
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answered by Rusty 2
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this is how my algebra teacher taught me how to do these..use the formula Y-y1=m(X-x1)
you see you plug in the x,y coordinates into the y1 and x1 and plug the slope into the m and just solve for Y like this:
Y-y1=m(X-x1)
Y-2=2(x-3) plug in the numbers
y-2=2x-6 simplify the equation..
+2 +2 add 2 to both sides..
then you get Y=2x-4 which is R.. so there you go hope i helped..
2006-12-26 01:37:57
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answer #4
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answered by J.J. 2
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Oh man, it's been years since I've taken a math class. I remember graphing calculators being helpful for gems like this.
2006-12-26 01:09:19
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answer #5
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answered by pinwheelbandit 5
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go www.graphamatica.com and download the software. it can solve all these types of qns cos u don have a graphing calc.
2006-12-26 02:46:35
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answer #6
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answered by Matthew N 5
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