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2006-12-25 17:01:41 · 3 answers · asked by casedood2k4 1 in Science & Mathematics Mathematics

3 answers

0.002 + e^(iπ) + Σ1/2^n (for n = 1 to ∞) =
0.002 - 1 + 1 = 0.002

2006-12-25 19:11:27 · answer #1 · answered by Northstar 7 · 0 0

e^ipi = -1
the sum = 1 thus total 0.002

2006-12-26 01:18:06 · answer #2 · answered by gjmb1960 7 · 0 0

0.002 + e^(i pi) + (1/2)/[1-(1/2)] = 0.002 - 1 + 1 = 0.002

2006-12-26 01:09:26 · answer #3 · answered by sahsjing 7 · 0 0

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