2006-12-25 17:00:20 · 8 answers · asked by ves.pera 2 in Pets ➔ Other - Pets
Since you are clearly looking at what to do with this paddock....
The Agricultural community has a measure called a grazing unit or animal unit - a standard measure of approximately how much pasture the species needs for a season. A cow is one grazing unit, 5 sheep = one grazing unit. Now EXTREMELY good pasture will support one grazing unit per acre but more commonly it take 2 acre/grazing unit and in arid areas it can be many more acres. IF there is poor, rocky soil in your paddock or woods it will graze less animals. If you intend to supplement with purchased hay it will support more.
Id suggest you contact the county co-operative extension service in your area- this government office just made to give advice on thing like this (free). They will probably know average grazing capacity for your area and will probably be able to send someone to look you paddock over with their own two eyes & give more personal advice
2006-12-26 20:24:40 · answer #1 · answered by ragapple 7 · 0⤊ 0⤋
Sheep Per Acre
2016-12-18 11:58:40 · answer #2 · answered by rasavong 4 · 0⤊ 0⤋
This Site Might Help You.
RE:
I have a paddock which is 1 acre in size. How many sheep can I keep in this paddock??
2015-08-16 07:04:35 · answer #3 · answered by Raynell 1 · 0⤊ 0⤋
How Many Sheep Per Acre
2016-10-03 08:04:08 · answer #4 · answered by pozzi 4 · 0⤊ 0⤋
To answer this question you must first determine the animal requirements from the pasture and the available forage.
Daily Animal Dry Matter Requirements
Beef & Sheep - 3% of their body weight
Dairy - 3.5% - 4%
Animal Requirements from pasture = (A X B) - C
A = Total body weight of all animals
B = DM requirements per day
C = Supplemental Feeds (silage, hay, grain)
Available Forage = [(D - E) X F] X G
D = Forage Height in Paddock
E = Remaining Stubble
F = DM yield per acre (see chart below)
G = Utilization Rate (75% - 90%)
Dry Matter Yield/Acre (approximate)
Range - 100 - 500 pounds of DM per inch of growth
* Dependent upon plant density/acre
* Average figure is 300 pounds per inch of growth
Example:
250 ewes @ 150 pounds each = 37,500 pounds of body weight
37,500 X 3% = 1,125 pounds of dry matter (DM) needed.
Pasture at 6" tall X 350# DM = 2100# DM
Leave Residual forage 600# (2 inch height)
2100# - 600# = 1500# Available for grazing
1500# DM X 75% (25% wastage) = 1,125# available DM
Therefore, I acre with I, 125# of available DM will supply the DM requirements of the 250 ewes for one day.
2006-12-25 17:11:23 · answer #5 · answered by Webmaster Tim 2 · 0⤊ 1⤋
paddock? you no they can get out of near any sort of thing whats your paddock consist of need more info.
2016-03-18 00:34:19 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Probably 3-7. Depends on the amount of grass you have or if you are just feeding hay.
2006-12-26 07:36:30 · answer #7 · answered by hey_its_from_clare 3 · 0⤊ 0⤋
Alot.
2006-12-25 17:10:22 · answer #8 · answered by Anonymous · 0⤊ 0⤋