I am off tomorrow but have to return to work wednesday. I work in retail so my days off vary and I just happened to get days off on each side of Christmas.
2006-12-25 15:59:11 · 19 answers · asked by reallyfedup 5 in Society & Culture ➔ Holidays ➔ Other - Holidays
I have to work Tuesday but will be able to take off the rest of the week. Where I work some of the leave is the "use it or lose it" by the end of the year variety. I'm glad you get a nice long holiday too, and I hope your Christmas was happy.
2006-12-26 00:52:07 · answer #1 · answered by AnOrdinaryGuy 5 · 0⤊ 0⤋
Nope, I've been retired since 1994 and enjoying every minute. The last few years that I worked we were undergoing a down sizing process that I found to be very disgusting as many of my fellow workers were either fired or transferred to other jobs at a lessor salary. I retired early with a pension that was 1/3 of what I was promised but it is better than nothing.
2006-12-26 00:16:42 · answer #2 · answered by Anonymous · 0⤊ 0⤋
I'm off tomarrow as well. Come Wednesday at 8:00 AM.
2006-12-26 00:17:54 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Yep in at 9:45 AM
2006-12-26 00:01:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
LOL I'm a mom . I didn't even get Christmas off.
2006-12-26 00:08:02 · answer #5 · answered by sassygrrll7 4 · 0⤊ 0⤋
No, I GET to go back to work tomorrow! I'm blessed to have a job!
2006-12-26 00:06:51 · answer #6 · answered by Malone 7 · 0⤊ 0⤋
I took the whole week off from work this week.
2006-12-26 00:09:17 · answer #7 · answered by Lisa 2 · 0⤊ 0⤋
i dont work till january 10, it suxs but i get all that time off
2006-12-26 00:03:23 · answer #8 · answered by Kaitlyn 2 · 0⤊ 0⤋
Yeah... in at 8 am. It really sucks but I've got no choice... and i'm starting to get really pissed at it.
2006-12-26 00:21:20 · answer #9 · answered by somedudefromthesouth 2 · 0⤊ 0⤋
yes, i am at work now. the good thing is, there is something else to look forward to, and that something is New Year's!
2006-12-26 00:06:34 · answer #10 · answered by Anonymous · 0⤊ 0⤋