Marginal revenue. A defense attorney charges her client $4000 plus $120 per hour. The formula R = 120n + 4000 gives her revenue in dollars for n hours of work.
What is her revenue for 100 hours of work?
What is her revenue for 101 hours of work?
By how much did the one extra hour of work increase the revenue? (The increase in revenue is called the marginal revenue for the 101st hour.)
2006-12-25 14:30:34 · 6 answers · asked by salarian2001 2 in Science & Mathematics ➔ Mathematics
What is her revenue for 100 hours of work?
r = 120n+4000
r = 120(100) +4000
r = 12000+4000
r =16000
What is her revenue for 101 hours of work?
r = 120n+4000
r = 120(101) +4000
r = 12120+4000
r =16120
By how much did the one extra hour of work increase the revenue?
r2-r1= 120
There you go, kid.
Do your own homework next time.
2006-12-25 14:48:01 · answer #1 · answered by frosty666_slut 2 · 0⤊ 0⤋
For 100hrs = 120*100+4000 = 16000
The extra hour just increases it by 120
2006-12-25 14:39:24 · answer #2 · answered by Andy 2 · 0⤊ 0⤋
$4000 plus $120 per hour
so if she worked one hour : 4000 + 120
2 hours : 4000 + 2 times 120
3 hour : 4000 + 3 times 120
this is exactly the formula : earning = 4000 + numberofhours times 400
with this info you should be able to make your problem
2006-12-25 16:58:51 · answer #3 · answered by gjmb1960 7 · 0⤊ 0⤋
You do not need to calculate and solve the equations...
Simple....
Hourly rate (what one earns for every hour worked) is $ 120 and the difference between 100 hours and 101 hours is....of course, 1 hour.
So, the marginal revenue is $ 120 (hourly rate).
2006-12-25 15:49:57 · answer #4 · answered by moksha 2 · 0⤊ 0⤋
n = hours
So first, R=120(100) + 4000
.. and so on...
2006-12-25 14:39:24 · answer #5 · answered by Anonymous · 0⤊ 0⤋
You just put 100 in place of n,=16,000.
Then you put 101 for n,=16,120
2006-12-25 14:40:49 · answer #6 · answered by Kreutzer 4 · 0⤊ 0⤋