s>t
2006-12-25 09:44:01
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answer #1
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answered by raj 7
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s = t + 4
this means that what ever t is, s is 4 greater than t.
Thus s > t.
This reminds me of the time that
I had to prove that
if a < b then
a + c < b + c.
It took me a long time to figure out what I could use in the proof that was even simpler than what I had been asked to prove.
a < b means that b - a is a positive number.
The sum of two positive numbers is positive.
Suppose that a < b.
Now from this we prove that a + c < b + c as follows.
(b + c ) - (a + c ) = b + c - a - c = b - a + c - c = b - a + 0
= b - a which is a positive number because a < b.
(b + c) - (a + c) is a positive number.
Hence (a + c) < (b + c)
2006-12-25 19:48:05
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answer #2
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answered by kermit1941 2
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s>4=s-4
2006-12-25 17:44:02
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answer #3
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answered by Anonymous
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/1/ suppose s
\2\ suppose s=t, now subtract 2 equals off both sides, then s-s=t-t-4 or 0=-4: false!
/3/ suppose s>t, now subtract 2 equals off both sides, then s-s>t-t-4 or 0>-4: true!
2006-12-25 20:25:54
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answer #4
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answered by Anonymous
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s exceeds t by 4 so s > t.
2006-12-25 18:10:28
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answer #5
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answered by steiner1745 7
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Think about what happens when t=0.
2006-12-25 17:45:02
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answer #6
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answered by modulo_function 7
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s is equal to t, plus 4 more.
s is more than t.
2006-12-25 17:46:39
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answer #7
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answered by S. B. 6
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Not really sure what you're getting at. The only thing one can say is s>t. How about s=s>t
2006-12-25 18:05:12
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answer #8
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answered by Princess Marianna 1
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s > t
2006-12-26 01:24:07
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answer #9
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answered by Northstar 7
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s>t
2006-12-25 18:49:10
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answer #10
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answered by yashodauk 2
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