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8 answers

Geometrically possible....solid geometry i mean

Arrange them as a "regular pentahedron"

5 identical particles in space with equal distance to each other in case of aregular pentahedron.

2006-12-24 23:58:42 · answer #1 · answered by Som™ 6 · 0 1

It's actually impossible in 3 dimensions. All of the other answers will leave at least two of the particles further away from each other than two other particles. For example, in a square or a pentagon, a particle will be closer to its neighbors than to the particles on the opposite sides.

The most particles you can do this with is 4, and that's a tetrahedron. Basically, take a cube and put them in two corners on one face, and then on the opposite face, put the other two particles in the corners NOT directly below/above the corners you placed the first two in.

2006-12-25 08:49:21 · answer #2 · answered by mrsocialist 2 · 3 0

I don't get the question, but all of them an equal distance from each other? I don't think it's possible... the pentagon means that only some of the points are equidistant, and the square with a point in the center means the diagonals going through the center will never equal the sides of the square. I don't think it's possible.

2006-12-26 17:20:45 · answer #3 · answered by Wufei 3 · 1 0

Not possible in 3D..
In 3D u can arrange a maximum of 4 particles equidistant from one another..not 5.

Should be possible in 4D.

2006-12-29 06:41:46 · answer #4 · answered by *♥* Preethi :-) *♥* 2 · 0 0

i think this can be done by placing the 4 particles in a square formation. In the center, at intersection of the diagonals, place the fifth particle.

I hope this helps.

2006-12-25 07:51:46 · answer #5 · answered by GorbanZus 3 · 0 2

Put them in the corners of a pentagon.

2006-12-25 07:52:32 · answer #6 · answered by debdd03 2 · 0 2

Not possible in 3D, requires 4D

2006-12-25 09:53:45 · answer #7 · answered by Defunct 2 · 1 0

Not easy to set this, but can be done.

2006-12-25 07:49:34 · answer #8 · answered by M.R.Palaniappa 2 · 0 2

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