Geometrically possible....solid geometry i mean
Arrange them as a "regular pentahedron"
5 identical particles in space with equal distance to each other in case of aregular pentahedron.
2006-12-24 23:58:42
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answer #1
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answered by Som™ 6
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It's actually impossible in 3 dimensions. All of the other answers will leave at least two of the particles further away from each other than two other particles. For example, in a square or a pentagon, a particle will be closer to its neighbors than to the particles on the opposite sides.
The most particles you can do this with is 4, and that's a tetrahedron. Basically, take a cube and put them in two corners on one face, and then on the opposite face, put the other two particles in the corners NOT directly below/above the corners you placed the first two in.
2006-12-25 08:49:21
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answer #2
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answered by mrsocialist 2
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I don't get the question, but all of them an equal distance from each other? I don't think it's possible... the pentagon means that only some of the points are equidistant, and the square with a point in the center means the diagonals going through the center will never equal the sides of the square. I don't think it's possible.
2006-12-26 17:20:45
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answer #3
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answered by Wufei 3
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Not possible in 3D..
In 3D u can arrange a maximum of 4 particles equidistant from one another..not 5.
Should be possible in 4D.
2006-12-29 06:41:46
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answer #4
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answered by *♥* Preethi :-) *♥* 2
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i think this can be done by placing the 4 particles in a square formation. In the center, at intersection of the diagonals, place the fifth particle.
I hope this helps.
2006-12-25 07:51:46
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answer #5
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answered by GorbanZus 3
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Put them in the corners of a pentagon.
2006-12-25 07:52:32
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answer #6
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answered by debdd03 2
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Not possible in 3D, requires 4D
2006-12-25 09:53:45
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answer #7
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answered by Defunct 2
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Not easy to set this, but can be done.
2006-12-25 07:49:34
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answer #8
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answered by M.R.Palaniappa 2
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