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hyberbola

2006-12-24 21:18:08 · 7 answers · asked by vagabond84 1 in Science & Mathematics Mathematics

7 answers

(x - 24) (y - 36) = 240

Divide both sides by (x - 24) to get
y - 36 = 240 / (x - 24)

Add 36 to both sides to get

y = 240/(x - 24) + 36

This is indeed a hyperbola, but what you have to calculate are the x and y asymptotes.

To solve for the x-asymptote, equate the denominator of the fraction to 0 (after all, this is where the function is undefined). Thus, x - 24 = 0, which implies x = 24, which is our vertical asymptote.

To solve for the y-asymptote, all you have to do is look at the number added to the fraction. In this case, it's 36. So y = 36 is the horizontal asymptote.

All you have to do is solve the y and x intercepts and then the hyperbola will be graphable.

2006-12-24 21:26:15 · answer #1 · answered by Puggy 7 · 0 0

(x-24) (y-36) = 240
(y-36) = 240/(x-24)
y = 240/(x-24) + 36

x > 24 or x < 24
y correspond with x's value.

There is more than 1 solution.

2006-12-24 21:54:38 · answer #2 · answered by PIPI B 4 · 0 0

y-36=240/[x-24]
y=240/[x-24]+36
it is a curve of the type
y=1/x
This is not a hyperbola whose
equation is of the type
[x-xo]^2/a^2-[y-yo]^2/b^2=1

2006-12-25 02:50:25 · answer #3 · answered by openpsychy 6 · 0 1

It is not right to say ( X-24 ) (y-36)=240
because u have too many answers

you have to add another one like x +5y=320

thanks

2006-12-25 04:18:50 · answer #4 · answered by mzb_abtah 1 · 0 0

x=28 and y=96

2006-12-24 21:32:05 · answer #5 · answered by Anonymous · 0 0

This is a question or a statement?

I don't think this is the equation of a parabola. A parabolic function is of the form:
(x-a)^2 - (y-b)^2 = c^2

2006-12-24 23:58:57 · answer #6 · answered by Arc 2 · 0 1

Y = +-6.67
X = +-10
Was that your question?

2006-12-24 21:28:17 · answer #7 · answered by Anata B 1 · 0 0

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