2006-12-24 19:59:46 · 9 answers · asked by Tavia E 1 in Science & Mathematics ➔ Mathematics
Let
V = Volume of water
d = Diameter of pool
r = Radius of pool
h = depth of water in pool (height of water)
d = 18 feet
h = 4 feet
r = d/2 = 9 feet
V = πr²h = π(9²)(4) = π(81)(4) = 324π = 1017.876 ft³
2006-12-24 20:07:09 · answer #1 · answered by Northstar 7 · 1⤊ 0⤋
Volume = Area of pool surface * depth
= pi * (18/2)^2 * 4
= pi * 81 * 4
= 1017.876 cubic feet
2006-12-24 20:07:53 · answer #2 · answered by Mattvayne 3 · 0⤊ 0⤋
PEOPLE!!!!
He said it is a ROUND POOL! It is a cylinder (like a can of Tuna!)
There are only two dimensions: Height and width!
Volume of a cylinder:
(¶R^2) x H
Width (Diameter) is 18 feet, so Radius is half of that, or 9 feet.
(R^2)= 9x9 = 81
81 x ¶ (which is 3.14159) = 254.46879 sq ft
254.46879 x H (which is 4) = 1017.8760 cu ft.
Source: 7th grade algebra class.
Link to figure it out faster than I did:
http://grapevine.abe.msstate.edu/~fto/tools/vol/cylinder.html
2006-12-24 20:03:59 · answer #3 · answered by Big Mack 4 · 0⤊ 0⤋
diameter=18'
so radius r = 9'
so volume = pi*r^2*h
= 3.142*81*4= 1018 cubic feet
2006-12-24 20:08:51 · answer #4 · answered by ravish2006 6 · 0⤊ 0⤋
The radius is 9 feet. You search the area of the base of the formed cylinder. You obtain 81pi.
You multiply this by the height (depht). You obtain 324pi.
And now you look at your answers and you smile: "What was so hard to do?"
2006-12-25 00:13:43 · answer #5 · answered by Arc 2 · 0⤊ 0⤋
In order to have cubic feet you need 3 dimensions.
2006-12-24 20:06:36 · answer #6 · answered by Charlie-chan 1 · 0⤊ 4⤋
you need to know length, height/depth, and width. volume= height/depth x width x length.
the length is pie x diameter (which is 18 feet)
the answer is in cubic feet.
2006-12-24 20:03:27 · answer #7 · answered by 89 3 · 0⤊ 2⤋
1017.36
2006-12-24 20:03:03 · answer #8 · answered by naejplman 2 · 0⤊ 0⤋
226.08 c.f.
2006-12-24 20:11:17 · answer #9 · answered by Wabbit 5 · 0⤊ 0⤋