describe what you would see if u added:?

Question

a) a piece of zince metal to a test tube that contains 6 Molar hydrochloric acid
b) a piece of copper metal to another test tube that contains 6 molar hydrochloric acid
c)concentrated nitric acid added to a test tube containing a piece of copper metal.

Answer 1

a) the zinc metal would dissolve[Zn(s)+HCl(l)-->ZnCl(l)+H2(g)]

b)Does not react[Cu(s)+HCl(l)-->Cu(s)+HCl(l)] because the acid is not strong enough to break the bonds of copper

c)The copper is oxidizedCu(s) + 4HNO3(aq) ——> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

Answer 2

1) Zn(s) + HCl(aq) --> ZnCl2(aq) + H2(g)
A convenient way of making hydrogen gas if you are not
bothered by a little HCl(g) in it.

2) Cu(s) + HCl(aq) --> no reaction
Copper is not an "active" metal and will not react with
protonic acids. Neither will Ag, Pt, and Au

3) Copper will be oxidized to Cu2+ ion by the nitric acid which will itself be reduced to either NO or NO2 or a mixture of the two gases along with H2O. I have seen both products in different chemistry books.

Answer 3

in a and c there will be efferversence in b there is no reaction as copper is less reactive than hydrogen.
a) Zn + HCl = ZnCl + H2

Dont know about c